javascript - 通过 jQuery ajax 将 jQuery 构造的数组发送到 PHP

Question

我似乎无法让这个对象通过 jQuery 的 ajax 传递到我的 PHP 文件。

$("body").on("submit", ".upload-results-form", function(){

        var photosJSON = [];

$(".upload-result-wrapper .upload-results .photos li").each(function(){

    var photoID = $(this).attr("rel");
    var description = $(".photo-upload-description", this).val();
    var source = $("img", this).attr("src");

    photosJSON.push({photoID: photoID, description: description, source: source});

});

var jsonData = JSON.stringify(photosJSON);


    $.ajax({
    type: "POST",
    url: "ajax/add/albums/photos_publish.php",
data: "photosJSON="+jsonData,
    cache: false,
    success: function(html){
        alert(html);        
    }
    });

}); 

我的 jsonData 看起来像这样:

[{"photoID":"47","description":"","source":"photos/50611a8725cca_224.jpg"},
{"photoID":"48","description":"","source":"photos/50611a8764881_224.jpg"},
{"photoID":"49","description":"","source":"photos/50611a87aa508_224.jpg"},
{"photoID":"50","description":"","source":"photos/50611a88dd34b_224.jpg"}]

和我的 php 文件:

$photosJSON = json_decode($_POST['photosJSON']);
echo $photosJSON['photoID'];

但是没有返回任何内容，似乎没有任何内容被发送到 php。

Answer 1

您必须将 javascript 对象转换为 JSON:

data: {photoDescriptions: JSON.stringify(photoDescriptions)},

然后，在您的 PHP 代码中:

$photoDescriptions = json_decode($_POST['photoDescriptions']);