下面您将看到一些代码,用于为 extjs 4 应用程序设置当前登录的用户。如果我未注释警报,则代码似乎会等到警报被接受后才继续执行(看起来)。这样就有足够的时间让异步调用成功完成。如果我注释掉该警报,则变量“employeeFilter”永远不会被设置,因为 AJAX 调用没有及时返回。在这种情况下,它将“employeeFilter”设置为 null。我该如何解决这个问题,以便它等到 AJAX 响应成功返回?
var loggedInUserId = null;
Ext.Ajax.request({
url: '/Controls/UserList/UserService.asmx/GetLoggedInUserId',
method: 'POST',
jsonData: { 'x': 'x' },
success: function (response, opt) {
loggedInUserId = Ext.decode(response.responseText).d;
},
failure: function (response) {
}
});
//alert(loggedInUserId);
var employeeFilter = loggedInUserId;
var projectFilter = '-1';
最佳答案
我会这么做的。
var employeeFilter;
Ext.Ajax.request({
url: '/Controls/UserList/UserService.asmx/GetLoggedInUserId',
method: 'POST',
jsonData: { 'x': 'x' },
success: function (response, opt) {
employeeFilter = Ext.decode(response.responseText).d;
//Do here whatever you need to do once the employeeFilter is set. probably call a function and pass the employee filter as parameter.
},
failure: function (response) {
}
});
var projectFilter = '-1';
关于javascript - 等待 Ext.Ajax.request 成功响应后再设置变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12810076/