此代码旨在根据按钮单击来显示和隐藏表格，但是，它似乎无法正确切换它。有人知道我做错了什么吗？
<body>
<br>
<button onclick="toggleTable();" style="position:absolute; top:130px; left:1000; width:200px; height:25px">3-D Model</button>
<br>
</body>
<script>
function toggleTable()
{
var status = document.getElementById("modelTable").style.display;
if (status == 'block') {
document.getElementById("modelTable").style.display="none";
} else {
document.getElementById("modelTable").style.display="block";
}
}
<table id="modelTable" border="1" align="right" style="display:block; position:absolute; top:150px; left:1000;">
<tr>
<th>
<a href="google.com"> 3-D Model </a>
</th>
</tr>
<tr>
<td>
<a>test1</a>
</td>
</tr>
<tr>
<td>
<a>test2</a>
</td>
</tr>
</table>
</script>
最佳答案
您的标记无效，您需要将表格放在正文中
<body>
<br/>
<button onclick="toggleTable();" style="position:absolute; top:130px; left:1000; width:200px; height:25px">3-D Model</button>
<br/>
<table id="modelTable" border="1" align="right" style="display:block; position:absolute; top:150px; left:1000;">
<tr>
<th> <a href="google.com"> 3-D Model </a>
</th>
</tr>
<tr>
<td> <a>test1</a>
</td>
</tr>
<tr>
<td> <a>test2</a>
</td>
</tr>
</table>
<script>
function toggleTable() {
var table = document.getElementById("modelTable");
var status = table.style.display;
if (status == 'block') {
table.style.display = "none";
} else {
table.style.display = "block";
}
}
</script>
</body>
演示:Fiddle
关于javascript - OnClick 事件表无法正确触发，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20256957/