我在将一些值传递到 php 页面时遇到问题，不知道出了什么问题，只知道错误发生在 xmlhttp.open 处。尝试了很多东西，无法弄清楚。
代码如下: html:
<html>
<head>
<script>
function getVote(i, j) {
if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else {// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState==4 && xmlhttp.status==200) {
document.getElementById("poll").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","poll_vote.php?vote1="+i+"&vote2="+j,true);
xmlhttp.send();
//document.write(i + ' ' + j);
}
</script>
</head>
<body>
<div id="poll">
<h3>Are you a skier, or do you get stout on the board mon? Either way, lets see if shred...</h3>
<form>
What do you do?<br>
Ski:
<input type="radio" name="vote1" id="vote1" value="0" >
<br>Snowboard:
<input type="radio" name="vote1" id="vote1" value="1">
<br>Dream of getting rad:
<input type="radio" name="vote1" id="vote1" value="2">
<br>
Do you watch other people hit the jump first?<br>
Yes:
<input type="radio" name="vote2" id="vote2" value="0" onclick="var tmpora = document.getElementById('vote1').value; getVote(tmpora, this.value);">
<br>No:
<input type="radio" name="vote2" id="vote2" value="1" onclick="var tmpora = document.getElementById('vote1').value; getVote(tmpora, this.value);">
<br>
</form>
</div>
</body>
</html>
和 PHP:
<?php
$vote1 = $_REQUEST['vote1'];
$vote2 = $_REQUEST['vote2'];
$filename = "poll_result.txt";
$content = file($filename);
$array = explode("||", $content[0]);
$ski = $array[0];
$board = $array[1];
$no = $array[2];
$radski = $array[3];
$radboard = $array[4];
if ($vote1 == 0) {
$ski = $ski + 1;
} else if ($vote1 == 1) {
echo "howdyyy";
$board = $board + 1;
} else if ($vote1 == 2) {
$no = $no + 1;
}
if ($vote2 == 0) {
if ($ski == 1) {
$radski = $radski + 1;
} else if ($board == 1) {
$radboard = $radboard + 1;
} else if ($no == 1) {
}
$no = $no + 1;
} else if ($vote2 == 1) {
}
$insertvote = $ski."||".$board"||".$no"||".$radski"||".$radboard;
$fp = fopen($filename,"w");
fputs($fp,$insertvote);
fclose($fp);
?>
<h2>Result:</h2>
<table>
<tr>
<td>Skiers:</td>
<td>
<img src="poll.gif"
width='<?php echo(100*round($ski/($ski+$board+$no),2)); ?>'
height='20'>
<?php echo(100*round($ski/($ski+$board+$no),2)); ?>%
</td>
</tr>
<tr>
<td>Snowboarders:</td>
<td>
<img src="poll.gif"
width='<?php echo(100*round($board/($ski+$board+$no),2)); ?>'
height='20'>
<?php echo(100*round($board/($ski+$board+$no),2)); ?>%
</td>
</tr>
<tr>
<td>Dreamers:</td>
<td>
<img src="poll.gif"
width='<?php echo(100*round($no/($ski+$board+$no),2)); ?>'
height='20'>
<?php echo(100*round($no/($ski+$board+$no),2)); ?>%
</td>
</tr>
<tr>
<td>Rad Skiers:</td>
<td>
<img src="poll.gif"
width='<?php echo(100*round($radski/($ski+$board+$no),2)); ?>'
height='20'>
<?php echo(100*round($radski/($ski+$board+$no),2)); ?>%
</td>
</tr>
<tr>
<td>Rad Snowboarders:</td>
<td>
<img src="poll.gif"
width='<?php echo(100*round($radboard/($ski+$board+$no),2)); ?>'
height='20'>
<?php echo(100*round($radboard/($ski+$board+$no),2)); ?>%
</td>
</tr>
</table>
和txt文件如:
0||0||0||0||0
这就像 w3schools 上的示例，但我是新人，仍在学习并好奇为什么我的代码现在不起作用。
感谢所有提供帮助的人!!
享受
最佳答案
好的，发现错误了。
将 PHP 文件中第 30 行的代码替换为:
$insertvote = $ski."||".$board."||".$no."||".$radski."||".$radboard;
您错过了 .(附加)符号。
这是我得到的输出。忽略网络错误(我没有图像)
希望对您有帮助!
关于javascript - ajax php javascript php页面打开，参数未传递，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22219105/