我有以下 CSV:
Title, Rating, Year, Genre
All Quiet on the Western Front,8.1,1930,"Drama , War"
Gone with the Wind,8.2,1939,"Drama , Romance , War"
The Wizard of Oz,8.2,1939,"Adventure , Family , Fantasy , Musical"
Fantasia,7.9,1940,"Animation , Family , Fantasy , Music"
Pinocchio,7.6,1940,"Animation , Adventure , Drama , Family , Fantasy , Music"
The Great Dictator,8.5,1940,"Comedy , Drama , War"
Citizen Kane,8.5,1941,"Drama , Mystery"
Dumbo,7.3,1941,"Animation , Family , Musical"
Bambi,7.4,1942,"Animation , Drama , Family"
Casablanca,8.7,1942,"Drama , Romance , War"
It's a Wonderful Life,8.7,1946,"Drama , Family , Fantasy"
Notorious,8.2,1946,"Drama , Film-Noir , Romance , Thriller"
All About Eve,8.4,1950,Drama
Cinderella,7.3,1950,"Animation , Family , Fantasy , Musical , Romance"
Alice in Wonderland,7.4,1951,"Animation , Adventure , Family , Fantasy , Musical"
Strangers on a Train,8.2,1951,"Crime , Film-Noir , Thriller"
Dial M for Murder,8.2,1954,"Crime , Thriller"
Knock on Wood,7,1954,Comedy
Seven Samurai,8.8,1954,"Action , Drama"
Lady and the Tramp,7.4,1955,"Animation , Adventure , Comedy , Family , Romance"
Rebel Without a Cause,7.8,1955,"Drama , Romance"
The Trouble with Harry,7.2,1955,"Comedy , Mystery"
Forbidden Planet,7.7,1956,"Action , Adventure , Sci-Fi"
The Ten Commandments,7.9,1956,"Adventure , Drama , History"
12 Angry Men,8.9,1957,Drama
我想要完成的是这个(我的头现在不能正常工作):
读取 CSV 并创建一个仅显示所有独特类型的数组(例如:戏剧、 war 、奇幻......而不重复数组中的类型)
在 CSV 中搜索具有特定流派的行。例如,如果我搜索“戏剧”,则只会显示第 4 列中具有“戏剧”值的行。 (不显示流派列)
按标题、评级或年份对 CSV 进行排序(不显示类型列)。
我正在通过以下方式读取 CSV:
$.ajax({
type: "GET",
url: "movies.csv",
dataType: "text",
success: function(data) {
var results = $.parse(data);
}
});
如果我执行 alert(JSON.stringify(results, null, 4))
,它将打印正确的信息。 JSON 对象如下所示:
{
"results": {
"fields": [
"Title",
" Rating",
" Year",
" Genre"
],
"rows": [
{
"Title": "All Quiet on the Western Front",
" Rating": 8.1,
" Year": 1930,
" Genre": "Drama , War"
},
{
"Title": "Gone with the Wind",
" Rating": 8.2,
" Year": 1939,
" Genre": "Drama , Romance , War"
},
{
"Title": "The Wizard of Oz",
" Rating": 8.2,
" Year": 1939,
" Genre": "Adventure , Family , Fantasy , Musical"
},
{
"Title": "Fantasia",
" Rating": 7.9,
" Year": 1940,
" Genre": "Animation , Family , Fantasy , Music"
所以我知道这部分正在发挥作用。我正在尝试创建一个数组,然后用流派值填充 SELECT 标记。然后,如果用户选择其中之一,它将再次搜索文件,但仅显示指定了流派的行。用户将能够按前 3 列对列表进行排序。我现在问这个问题是因为我的头(和视力)现在不太好。
最佳答案
类型选择
http://jsfiddle.net/coma/4N676/25/
var movies = new Movies(JSON.parse(gists.files.Movies.content));
var html = '<option>Filter by genre</option>';
movies.getGenres().forEach(function(genre) {
html += '<option value="' + genre + '">' + genre + '</option>';
});
$('#genre')
.html(html)
.change(function() {
var list = movies
.reset()
.filterByGenre(this.value)
.sortByTitleAsc()
.getList();
alert(JSON.stringify(list));
});
http://jsfiddle.net/coma/4N676/
基础
var Movies = function(movies)
{
var genres = [];
var ratingMin = Infinity;
var ratingMax = -1;
var yearMin = Infinity;
var yearMax = -1;
movies.forEach(function(movie, movieIndex) {
movie.Genre = movie.Genre.split(', ');
movie.Rating = parseFloat(movie.Rating);
movie.Year = parseInt(movie.Year, 10);
ratingMin = Math.min(movie.Rating, ratingMin);
ratingMax = Math.max(movie.Rating, ratingMax);
yearMin = Math.min(movie.Year, yearMin);
yearMax = Math.max(movie.Year, yearMax);
movie.Genre.forEach(function(genre, genreIndex) {
genre = $.trim(genre).toLowerCase();
movie.Genre[genreIndex] = genre;
if (genres.indexOf(genre) < 0) {
genres.push(genre);
}
genres.sort();
});
});
this.original = movies;
this.list = movies.slice();
this.ratingMin = ratingMin;
this.ratingMax = ratingMax;
this.yearMin = yearMin;
this.yearMax = yearMax;
this.genres = genres;
};
Movies.prototype.reset = function()
{
this.list = this.original.slice();
return this;
};
setter/getter
Movies.prototype.getList = function()
{
return this.list.slice();
};
Movies.prototype.getRatingRange = function()
{
return [this.ratingMin, this.ratingMax];
};
Movies.prototype.getRatingMax = function()
{
return this.ratingMax;
};
Movies.prototype.getRatingMin = function()
{
return this.ratingMin;
};
Movies.prototype.getYearRange = function()
{
return [this.yearMin, this.yearMax];
};
Movies.prototype.getYearMax = function()
{
return this.yearMax;
};
Movies.prototype.getYearMin = function()
{
return this.yearMin;
};
Movies.prototype.getGenres = function()
{
return this.genres.slice();
};
过滤器
Movies.prototype.filterByNumbers = function(property, number)
{
if ($.isNumeric(number)) {
this.list = this.list.filter(function(movie) {
return movie[property] === number;
});
}
if ($.isArray(number)) {
this.list = this.list.filter(function(movie) {
return movie[property] >= number[0]
&& movie[property] <= number[1];
});
}
return this;
};
Movies.prototype.filterByGenre = function(genre)
{
this.list = this.list.filter(function(movie) {
return movie
.Genre
.indexOf(genre.toLowerCase()) >= 0;
});
return this;
};
Movies.prototype.filterByTitle = function(title)
{
this.list = this.list.filter(function(movie) {
return movie
.Title
.toLowerCase()
.indexOf(title.toLowerCase()) >= 0;
});
return this;
};
Movies.prototype.filterByYear = function(year)
{
this.filterByNumbers('Year', year);
return this;
};
Movies.prototype.filterByRating = function(rating)
{
this.filterByNumbers('Rating', rating);
return this;
};
分拣机
Movies.prototype.sortAsc = function(property)
{
this.list.sort(function(a, b) {
return a[property] > b[property];
});
return this;
};
Movies.prototype.sortDesc = function(property)
{
this.list.sort(function(a, b) {
return a[property] < b[property];
});
return this;
};
Movies.prototype.sortByTitleAsc = function()
{
this.sortAsc('Title');
return this;
};
Movies.prototype.sortByTitleDesc = function()
{
this.sortDesc('Title');
return this;
};
Movies.prototype.sortByYearAsc = function()
{
this.sortAsc('Year');
return this;
};
Movies.prototype.sortByYearDesc = function()
{
this.sortDesc('Year');
return this;
};
Movies.prototype.sortByRatingAsc = function()
{
this.sortAsc('Rating');
return this;
};
Movies.prototype.sortByRatingDesc = function()
{
this.sortDesc('Rating');
return this;
};
使用
$.getJSON('https://api.github.com/gists/9803182', function(gists) {
var movies = new Movies(JSON.parse(gists.files.Movies.content));
movies
.filterByGenre('comedy')
.filterByYear([1954, 2000])
.sortByTitleDesc();
console.log('Filtered and sorted', movies.getList());
console.log('Original', movies.reset().getList());
});
关于javascript - 读取、搜索和排序所有 CSV 值,避免重复,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22676036/