javascript - 根据单选是或否选择显示或隐藏表单

Question

我正在尝试使用 Jquery 根据用户选择的内容显示或多或少的表单。如果用户选择"is"，则会显示更多表单。我计划用许多不同的顶级问题来做到这一点，然后根据是或否解锁更多问题。

在此链接中显示了我所拥有的内容。 http://jcsites.juniata.edu/students/bookhjr10/flashpoint/test2.html

我遇到的问题是，用户需要检查两次"is"才能使问题消失，但当用户检查“否”时，问题应该关闭。

代码: jQuery

$(document).ready(function(){


   $('.show_hide').showHide({            
        speed: 1000,  // speed you want the toggle to happen    
        easing: '',  // the animation effect you want. Remove this line if you dont want an effect and if you haven't included jQuery UI
        changeText: 0, // if you dont want the button text to change, set this to 0
        showText: 'Yes',// the button text to show when a div is closed
        hideText: 'No' // the button text to show when a div is open

    }); 


});

</script>

HTML 表单:

<form class="form-signin" role="form">
 I am having a Cloud My Office log in issue
<input type="radio" name="myofficeissue" id="0" value="No">No
<input type="radio" name="myofficeissue" class="show_hide" rel="#slidingDiv"  id="1" value="Yes">Yes
    <div id="slidingDiv">
        I am having a username and password issue.
      <input type="radio" name="passwordissue" id="passwordissue-0" value="No">No
      <input type="radio" name="passwordissue" class="show_hide" rel="#slidingDiv_2" id="passwordissue-1" value="Yes">Yes
    </div>   
 <a href="#" class="show_hide" rel="#slidingDiv_2"></a><br />
    <div id="slidingDiv_2">
    I need to reset my password
      <input type="radio" name="password" id="password-0" value="No" checked="checked" required> No
      <input type="radio" name="password" id="password-1" value="Yes" required>   Yes
      </br>
        My username needs updated.
      <input type="radio" name="username" id="username-0" value="No" checked="checked" required> No
      <input type="radio" name="username" id="username-1" value="Yes" required> Yes</br>
My account is locked out
<input type="radio" name="locked" id="locked-0" value="No" checked="checked" required> No
      <input type="radio" name="locked" id="locked-1" value="Yes" required> Yes</br>
I am experiencing other problems
      <input type="radio" name="other" id="other-0" value="No" checked="checked" required>No
      <input type="radio" name="other" id="other-1" value="Yes" required>Yes</br>
    </div> 
</div>

CSS

<style>

body{
font-family:Verdana, Geneva, sans-serif;
font-size:14px;}

#slidingDiv, #slidingDiv_2{
    display:none;
}


</style>

我的问题是。这是做这样的事情的最好方法吗？ 有没有办法让 No 选项关闭 div？ 任何帮助表示赞赏。

Answer 1

我可以看到你的项目变得相当复杂，所以我认为在 JavaScript 中包含所有逻辑并不是解决这个问题的正确方法。因此，我在 JavaScript 中创建了一种逻辑 Controller ，并将逻辑需求与一些数据属性分离到 html 中。

Here is the code in action.该解决方案现在非常灵活且易于维护。您所需要做的就是将需要出现和消失的部分包装在 div 中，并为它们提供一个名为 “data-view-conditions” 的属性。此属性可以包含需要满足才能显示的多个条件。

条件以逗号分隔，包含输入名称和所需值。依次用冒号分隔。这支持单选和复选框输入。您还可以仅提供不带值的名称，如果至少检查或选择了该输入而不关心值，则条件将“匹配”。以下是一些示例条件。

data-view-conditions="name"

data-view-conditions="name:1"

data-view-conditions="name:1,name2:3,name3:test"

data-view-conditions="name4:123,name5"

JavaScript:

jQuery(function($){

  // Prevents errors in old IE.
  if(!window.console || !window.console.log) window.console = {log: function(){}};

  // Enable debugging for complex logic.
  var debug = true;

  function checkConditions(inputs, views){
    views.each(function(){
      var view = $(this);
      var conditions = view.attr('data-view-conditions').split(',');
      var display = true;

      // Loop over all required conditions to be met.
      for(var i = 0; i < conditions.length; i++){
        var name = conditions[i].split(':')[0];
        var value = conditions[i].split(':')[1];
        var input = inputs.filter('[name="' + name + '"]:checked');

        if(debug) console.log('\nRecalculating view conditions.');

        if(!input.length){
          display = false;
          if(debug) console.log('View not show as no :checked input with the name "' + name + '" was found.');
        }else{
          if(value != undefined && input.val() != value){
            display = false;
            if(debug) console.log('View not show as no :checked input with the name "' + name + '" has the value of "' + input.val() + '". Value needed was: "' + value + '".');
          }
        }
      }

      if(display){
        view.css({display: 'block'});
      }else{
        view.css({display: 'none'});
      }

    });
  }

  $('form').each(function(){
    var form = $(this);
    var inputs = form.find('input[type="checkbox"], input[type="radio"]');
    var views = form.find('[data-view-conditions]');

    // Recalculate which views to be shown each time the inputs change.
    inputs.on('change', function(e){
      checkConditions(inputs, views);
    });

    // Check conditions to set up required view state on page load.
    checkConditions(inputs, views);
  });

});

HTML:

<form>

  <label for="i1">Input 1</label>
  <input id="i1" type="radio" name="name1" value="1">

  <label for="i2">Input 2</label>
  <input id="i2" type="radio" name="name1" value="2">

  <div data-view-conditions="name1:2">
    <p>Hello</p>
    <label for="i3">Click me</label>
    <input id="i3" type="checkbox" name="name2">

    <div data-view-conditions="name2">
      <p>It works!</p>
    </div>
  </div>

</form>