我正在开发一个从数据库提取数据的页面。 PHP time() 被捕获并与用户内容一起保存到数据库中。
我想使用 JavaScript 从当前时间中减去 capturedTime 并显示帖子在 hr : min : s 中发布的时长，并且应该是居住。
HTML:
<div class = 'responses'>
<p class = 'capturedTime' style='display: none;'>123456789</p>
</div>
jQuery:
$(document).on('click', '.responses', function () {
$this = $( this );
timeC = $this.prev('.capturedTime').text();
timeNow = $.now()
timeLapsed = ( timeNow - timeC )/1000;
seconds = timeLapsed/60;
mins = seconds/60;
hrs = mins/24;
if ( timeLapsed !== NaN ){
alert(seconds + '------' + mins + '---' + hrs);
}
});
最佳答案
我建议您这样更改代码:
<body>
<div class='responses'>
<p class='capturedTime' data="1401270715145"></p>
</div>
</body>
var $times, timer;
$times = $('.capturedTime');
timer = setInterval(function () {
var i, len, cache, value, now, minutes, seconds;
for (i = 0, len = $times.length; i < len; i = i + 1) {
cache = $times.eq(i);
now = new Date().getTime();
value = new Date(now - parseInt(cache.attr("data")));
minutes = value.getMinutes();
seconds = value.getSeconds();
cache.html("m:" + minutes + " ss:" + seconds);
}
}, 1000);
关于javascript - 用 PHP 时间算出 JavaScript 时间，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23908194/