我们如何在 opencv 中制作晕影过滤器?我们需要为它实现任何算法还是只使用 BGR 的值?我们如何制作这种类型的过滤器。我看到了它的实现 here但我没看清楚。非常感谢任何人提供完整的算法指导和实现指导。
在 Abid rehman K
回答后,我在 c++ 中尝试了这个
int main()
{
Mat v;
Mat img = imread ("D:\\2.jpg");
img.convertTo(v, CV_32F);
Mat a,b,c,d,e;
c.create(img.rows,img.cols,CV_32F);
d.create(img.rows,img.cols,CV_32F);
e.create(img.rows,img.cols,CV_32F);
a = getGaussianKernel(img.cols,300,CV_32F);
b = getGaussianKernel(img.rows,300,CV_32F);
c = b*a.t();
double minVal;
double maxVal;
cv::minMaxLoc(c, &minVal, &maxVal);
d = c/maxVal;
e = v*d ; // This line causing error
imshow ("venyiet" , e);
cvWaitKey();
}
d
显示正确,但 e=v*d
行导致运行时错误
OpenCV Error: Assertion failed (type == B.type() && (type == CV_32FC1 || type ==
CV_64FC1 || type == CV_32FC2 || type == CV_64FC2)) in unknown function, file ..
\..\..\src\opencv\modules\core\src\matmul.cpp, line 711
最佳答案
首先,Abid Rahman K描述了使用此过滤器的最简单方法。你应该用时间和注意力认真研究他的回答。 维基百科对 Vignetting 的看法对于那些从未听说过此过滤器的人来说也很清楚。
Browny's实现this filter要复杂得多。但是,我将他的代码移植到 C++ API 并对其进行了简化,因此您可以自己按照说明进行操作。
#include <math.h>
#include <vector>
#include <cv.hpp>
#include <highgui/highgui.hpp>
// Helper function to calculate the distance between 2 points.
double dist(CvPoint a, CvPoint b)
{
return sqrt(pow((double) (a.x - b.x), 2) + pow((double) (a.y - b.y), 2));
}
// Helper function that computes the longest distance from the edge to the center point.
double getMaxDisFromCorners(const cv::Size& imgSize, const cv::Point& center)
{
// given a rect and a line
// get which corner of rect is farthest from the line
std::vector<cv::Point> corners(4);
corners[0] = cv::Point(0, 0);
corners[1] = cv::Point(imgSize.width, 0);
corners[2] = cv::Point(0, imgSize.height);
corners[3] = cv::Point(imgSize.width, imgSize.height);
double maxDis = 0;
for (int i = 0; i < 4; ++i)
{
double dis = dist(corners[i], center);
if (maxDis < dis)
maxDis = dis;
}
return maxDis;
}
// Helper function that creates a gradient image.
// firstPt, radius and power, are variables that control the artistic effect of the filter.
void generateGradient(cv::Mat& mask)
{
cv::Point firstPt = cv::Point(mask.size().width/2, mask.size().height/2);
double radius = 1.0;
double power = 0.8;
double maxImageRad = radius * getMaxDisFromCorners(mask.size(), firstPt);
mask.setTo(cv::Scalar(1));
for (int i = 0; i < mask.rows; i++)
{
for (int j = 0; j < mask.cols; j++)
{
double temp = dist(firstPt, cv::Point(j, i)) / maxImageRad;
temp = temp * power;
double temp_s = pow(cos(temp), 4);
mask.at<double>(i, j) = temp_s;
}
}
}
// This is where the fun starts!
int main()
{
cv::Mat img = cv::imread("stack-exchange-chefs.jpg");
if (img.empty())
{
std::cout << "!!! Failed imread\n";
return -1;
}
/*
cv::namedWindow("Original", cv::WINDOW_NORMAL);
cv::resizeWindow("Original", img.size().width/2, img.size().height/2);
cv::imshow("Original", img);
*/
img 的样子:
cv::Mat maskImg(img.size(), CV_64F);
generateGradient(maskImg);
/*
cv::Mat gradient;
cv::normalize(maskImg, gradient, 0, 255, CV_MINMAX);
cv::imwrite("gradient.png", gradient);
*/
maskImg 的样子:
cv::Mat labImg(img.size(), CV_8UC3);
cv::cvtColor(img, labImg, CV_BGR2Lab);
for (int row = 0; row < labImg.size().height; row++)
{
for (int col = 0; col < labImg.size().width; col++)
{
cv::Vec3b value = labImg.at<cv::Vec3b>(row, col);
value.val[0] *= maskImg.at<double>(row, col);
labImg.at<cv::Vec3b>(row, col) = value;
}
}
cv::Mat output;
cv::cvtColor(labImg, output, CV_Lab2BGR);
//cv::imwrite("vignette.png", output);
cv::namedWindow("Vignette", cv::WINDOW_NORMAL);
cv::resizeWindow("Vignette", output.size().width/2, output.size().height/2);
cv::imshow("Vignette", output);
cv::waitKey();
return 0;
}
什么是输出:
如上面的代码所述,通过改变firstPt
、radius
和power
的值,您可以获得更强/更弱的艺术效果。
祝你好运!
关于c++ - 在 opencv 中创建晕影过滤器?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22654770/