我知道有很多关于将 PHP 数组转换为 Javascript 的问题,标准答案如下:
tempary=<?php echo json_encode($tmpary); ?>;
但是,当我尝试访问数组时,无法访问元素。例如
document.write(tempary[2]); //debug
尽管我知道有第三个元素。
这是实际的代码:
global $wpdb;
$query="SELECT * FROM wp_ta_members";
$member_table=$wpdb->get_results($query);
echo "<p>Size of wp_ta_members table is " . count($member_table) . "</p>"; //debug
?>
<script type="text/javascript">
var members = [];
var tempary = [];
</script>
<?php
foreach ($member_table as $member_row)
{
$tmpary=array($member_row->member_id,
($member_row->current==1)?"current":"not a member",
$member_row->date_joined,
$member_row->title,
$member_row->first_names,
$member_row->last_names)
?>
<script type="text/javascript">
tempary=<?php echo json_encode($tmpary); ?>;
document.write(tempary[2]); //debug
console.log(tempary); //debug
members.push(tempary.concat());
</script>
<?php }
?>
您会注意到,我实际上正在创建一个数组数组,稍后我将使用以下循环对其进行处理:
for (mem in members)
{
document.write(workary.length + " " + members.length + " " + mem.length + " " + members[1] + "<br />"); //debug
document.write(mem[1] + " " + mem[2] + " " + mem[3] + " " + mem[4] +"<br />"); //debug
}
但是,对于 tempary[0],我得到的只是“1”,而对于任何其他元素,我得到的只是“未定义”。
如果我输出临时本身,我会得到一个由逗号分隔的所有元素组成的字符串。
我错过了什么?我希望 tempary 成为一个正确的 JavaScript 数组。
抱歉再次回来,但这仍然不起作用
我在脚本中添加了以下代码只是为了检查这个概念:
var a1 = [100, "scooby", "doo"];
var a2 = [200, "soup", "dragon"];
var a3 = [];
a3.push(a1);
a3.push(a2);
console.log(a3);
console.log(a3[0]);
console.log(a3[1]);
console.log(a3[1][0] + " " + a3[1][1]);
结果是:
[Array[3], Array[3]]
[100, "scooby", "doo"]
[200, "soup", "dragon"]
200 soup
这是正确的!
当我运行真实代码并执行这些行(在循环内)时:
console.log(tempary); //debug
members.push(tempary);
我得到结果:
["78", "current", "2014-01-01", "", "Fred", "Bloggs"]
这也是正确的(尽管我更喜欢将“78”存储为数字而不是字符串 - 但那是另一个故事了)。
但是,当我执行一个循环来打印数组数组的内容时,使用:
for (mem in members)
{
console.log(members.length + " " + mem.length + " " + members[1]); //debug
console.log(mem + " " + mem[0] + " " + mem[1] + " " + mem[2] + " " + mem[3] + " " + mem[4]); //debug
}
我得到一个重复的日志列表:
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
0 0 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
1 1 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
2 2 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
3 3 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
4 4 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
5 5 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
6 6 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
7 7 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
8 8 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
9 9 undefined undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
10 1 0 undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
11 1 1 undefined undefined undefined
1333 1 8000,current,2014-01-01,Ms,Joe,Soap
12 1 2 undefined undefined undefined
其中 1333 是成员数组中的数组数。 乔·索普是名单中的最后一个成员。 为什么console.log(mem);产生一个我不知道的递增数字。当这个数字达到两位数时,就会发生更奇怪的事情,例如12 使 mem[0] = 1 且 mem[1] =2 !! mem 的其余元素是“未定义”。
为了完整起见,以下是整个脚本:
<?php
/***** php and javascript to administer member details *****/
// **** get entire members table into a variable
global $wpdb;
$query="SELECT * FROM wp_ta_members";
$member_table=$wpdb->get_results($query);
echo "<p>Size of wp_ta_members table is " . count($member_table) . "</p>"; //debug
?>
<script type="text/javascript">
var members = [2000];
var tempary = [];
var a1 = ["100", "scooby", "doo"]; //test
var a2 = ["200", "soup", "dragon"]; //test
var a3 = []; //test
a3.push(a1); //test
a3.push(a2); //test
console.log(a3);
console.log(a3[0]);
console.log(a3[1]);
console.log(a3[1][0] + " " + a3[1][1]);
<?php
foreach ($member_table as $member_row)
{
$tmpary=array($member_row->member_id,
($member_row->current==1)?"current":"not a member",
$member_row->date_joined,
$member_row->title,
$member_row->first_names,
$member_row->last_names);
$x = 0;
foreach($tmpary as $value){
echo 'tempary[' . $x . '] = "' . $value . '";';
$x++;
}
?>
// tempary=JSON.parse("<?php echo json_encode($tmpary); ?>");
document.write(tempary[4] +"<br />"); //debug
console.log(tempary); //debug
members.push(tempary);
<?php }
?>
document.write(members + "<br />"); //debug
document.write("Hi Will again<br />"); //debug
for (mem in members)
{
console.log(members.length + " " + mem.length + " " + members[1]); //debug
console.log(mem + " " + mem[0] + " " + mem[1] + " " + mem[2] + " " + mem[3] + " " + mem[4]); //debug
}
</script>
我已经为此苦苦思索好几天了,但没有什么想法。任何帮助将不胜感激。
最佳答案
我发现您在每次迭代中都覆盖了临时数组。因此,当您进行 json_encode 时,您只剩下最后一项了。
试试这个:
global $wpdb;
$query="SELECT * FROM wp_ta_members";
$member_table=$wpdb->get_results($query);
echo "<p>Size of wp_ta_members table is " . count($member_table) . "</p>"; //debug
?>
<script type="text/javascript">
<?php
$members = array();
foreach ($member_table as $member_row){
$member = array(
$member_row->member_id,
($member_row->current==1)?"current":"not a member",
$member_row->date_joined,
$member_row->title,
$member_row->first_names,
$member_row->last_names
);
$members[] = $member;
}
?>
var members = <?php echo json_encode($members) ?>;
</script>
<?php }
?>
关于javascript - 将 PHP 数组转换为 JavaScript,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26546194/