我是 AngularJS 的新手,我决定通过尝试制作一个家谱应用程序/SPA 来开始学习。 出于测试目的,我将家谱数据硬编码到 $scope.personRegister 中。 我想做的第一件事是正确定位 personRegister 中的所有人员/节点,使用 ng-style 指令一次加载它们。
我在 Controller 内使用$filter,只返回第1000代中的人,并将过滤结果存储在名为test的新对象中。 然后,我打算将数据传递到应用程序外部的方法上,以定位节点。
问题是,当我操作 test 中的数据时,它也会操作 $scope.personRegister 中的原始数据,因此 View 也会更新。 为什么会出现这种情况?
<!-- borderbox is the subwindow -->
<div class="borderBox" style="left: 0px; top: 0px" ng-app="famTreeApp">
<!-- the content of the borderbox -->
<div class="insideContent" style="left: 100px; top: 0px">
<div ng-controller="famTree">
<div class="personBox" ng-repeat="name in personRegister"
ng-style="{'left':name.posX+'px', 'top':name.posY+'px' }">
{{name.fName}}
</div>
</div>
</div>
</div>
var familyTreeApp = angular.module("famTreeApp", []);
familyTreeApp.controller("famTree", function($scope, $filter, $log) {
//temp hard-coded data
$scope.personRegister = [
{id:1, genId:1000, gender:'M', fName:'John', momId:4, dadId:3, posX:'0', posY:'0' },
{id:2, genId:1000, gender:'F', fName:'Lisa', momId:4, dadId:3, posX:'0', posY:'0' },
{id:3, genId:999, gender:'M', fName:'Mark', momId:6, dadId:5, posX:'0', posY:'0' },
{id:4, genId:999, gender:'F', fName:'Sarah', momId:8, dadId:7, posX:'0', posY:'0' },
{id:5, genId:998, gender:'F', fName:'Martha', momId:0, dadId:0, posX:'0', posY:'0' },
{id:6, genId:998, gender:'M', fName:'James', momId:0, dadId:0, posX:'0', posY:'0' },
{id:7, genId:998, gender:'M', fName:'Frederick', momId:0, dadId:0, posX:'0', posY:'0' },
{id:8, genId:998, gender:'F', fName:'Georgiana', momId:0, dadId:0, posX:'0', posY:'0' },
{id:9, genId:1000, gender:'M', fName:'Trevor', momId:11, dadId:10, posX:'0', posY:'0' },
{id:10, genId:999, gender:'M', fName:'Andre', momId:8, dadId:7, posX:'0', posY:'0' },
{id:11, genId:999, gender:'F', fName:'Teresa', momId:0, dadId:0, posX:'0', posY:'0' },
{id:12, genId:1000, gender:'F', fName:'Shakira', momId:4, dadId:3, posX:'0', posY:'0' }
];
$scope.spouseRegister = [
{husbandId:3, wifeId:4, haveKids:1, currMarried:1},
{husbandId:6, wifeId:5, haveKids:1, currMarried:0},
{husbandId:7, wifeId:8, haveKids:1, currMarried:1},
{husbandId:10, wifeId:11, haveKids:1, currMarried:1}
];
$scope.test = $filter('filter')($scope.personRegister, {genId: 1000});
$log.log($scope.personRegister[1]); //message to console
$scope.test[1].posX = 50;
$scope.test[0].fName += 'ny Boy';
$log.log($scope.test[1]); //message to console
$log.log($scope.personRegister[1]); //message to console
//personPostioner(test);
});
http://jsfiddle.net/kq8xduj6/2/
如有任何帮助,我们将不胜感激。
最佳答案
您的数组包含的对象与 $scope.personRegister
和 $scope.test
引用的对象相同。是的,$filter返回一个新数组,但数组的内容仍然是相同的对象。如果您希望它们是不同的数据集,请过滤掉原始数组的副本。
$scope.test = $filter('filter')(angular.copy($scope.personRegister), {genId: 1000});
关于javascript - Angularjs: Controller 中的 $filter 返回的数据仍然与原始对象绑定(bind),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26855506/