javascript - 下划线返回数组中对象的索引，其中单词存在于对象内的句子中

Question

我有一个数组，里面有这样的数组；

    var lines = [
["1","1","1","A man is walking."]
,["1","1","2","Noooo he's not, no way!"],
["1","1","3","You can't see that far can you?"],
["1","1","4","I can, he stopped, he's looking right at us"]
];

如果 line[4] 正是搜索语句，例如“A man is Walking”，则使用 Underscore，我可以在“lines”内获取一个数组。将返回行[0]；

所以我希望能够只用一个单词搜索这些句子(行)，比如“Walking”应该匹配并返回“lines”中的第一个数组，因为有一个句子包含该单词。

_.some(lines, function(array){
            var result = (array[4] == 'walking' && array[4]);
        if (result !== false){
                console.log(result);
            } 
});

我如何修改这个下划线函数，或者是否应该使用正确的函数，或者如果有的话，即使它没有下划线，请提出建议。

Answer 1

假设你没有 ES6 的 find 功能，用简单的 javascript 表示:

var lines = [
["1","1","1","A man is walking."],
["1","1","2","Noooo he's not, no way!"],
["1","1","3","You can't see that far can you?"],
["1","1","4","I can, he stopped, he's looking right at us"]
];

function lineSearch(arr, term) {
  var indices = arr.map(function(innerArr, index) {
    return innerArr[3].indexOf(term) > -1 ? index : null;
  }).filter(function(x) {
    return x !== null;
  });

  var results = arr.map(function(innerArr, index) {
    return innerArr[3].indexOf(term) > -1 ? innerArr : null;
  }).filter(function(x) {
    return x !== null;
  });

  return {indices: indices, results: results};
}

console.log(lineSearch(lines, "can"));

应该给出:

 {
  indices: [2, 3],
  results: [["1", "1", "3", "You can't see that far can you?"], ["1", "1", "4", "I can, he stopped, he's looking right at us"]]
 }