javascript - 基于For循环迭代的数组拼接

标签 javascript arrays object for-loop splice

我正在尝试获取一个数组(“selectedWorkshops”),并将其中的对象移动到“registeredWorkshops”。然后,我还想从“selectedWorkshops”和另一个简单地称为“workshops”的数组中删除这些对象。

在此处查看我的代码笔:http://codepen.io/trueScript/pen/wBVqNN

数组:

var workshops = [
  {
    name: 'apples',
    WorkshopId: '19'
  },
  {
    name: 'oranges',
    WorkshopId: '3b'
  },
  {
    name: 'pears',
    WorkshopId: 'x6'
  },
  {
    name: 'pineapples',
    WorkshopId: '55'
  },
  {
    name: 'watermelons',
    WorkshopId: '8v'
  }
];

var selectedWorkshops = [
  {
    name: 'oranges',
    WorkshopId: '3b'
  },
  {
    name: 'watermelons',
    WorkshopId: '8v'
  },
  {
    name: 'pears',
    WorkshopId: 'x6'
  }
];

var registeredWorkshops = [];

应该将研讨会移动到“registeredWorkshops”并将其从“selectedWorkshops”和“workshops”中删除的函数:

flipWorkshops = function(){
    var numberOfWorkshops = selectedWorkshops.length;
    var X = 1;
    for(var i = 0; i < numberOfWorkshops; i++ ){
        registeredWorkshops.push(selectedWorkshops[i]);
        for(var j = 0, arrayLength = workshops.length; j < arrayLength; j++) {
            var selectedWorkshop = selectedWorkshops[i];
            var originalWorkshop = workshops[j];
            if(selectedWorkshop == originalWorkshop){
                var matchingWorkshop = j;
                workshops = workshops.splice(j, 1);
                selectedWorkshops = selectedWorkshops.splice(i, 1);
            }
        }
    }
};
flipWorkshops();

为什么对象没有像应有的那样从“workshop”和“selectedWorkshops”数组中正确拼接出来?我做错了什么?

最佳答案

“splice() 方法向数组添加项目或从数组中删除项目,并返回删除的项目。” http://w3schools.com/jsref/jsref_splice.asp因此,基本上,您将研讨会简化为单个对象,即删除的数组元素。

相反,更改:

workshops = workshops.splice(j, 1);
selectedWorkshops = selectedWorkshops.splice(i, 1);

...至:

workshops.splice(j, 1);
selectedWorkshops.splice(i, 1);

JSFiddle

<小时/>

也许这就是你想要的:

var registeredWorkshops = [];
var flipWorkshops = function(){
    var numberOfWorkshops = selectedWorkshops.length;
    var X = 1;
    for(var i = numberOfWorkshops - 1; i >= 0; i-- ){
        registeredWorkshops.push(selectedWorkshops[i]);
        var selectedWorkshop = selectedWorkshops[i];
        for(var j = workshops.length - 1; j >= 0; j--) {
            var originalWorkshop = workshops[j];
            if(selectedWorkshop.name == originalWorkshop.name &&
              selectedWorkshop.WorkshopId == originalWorkshop.WorkshopId){
                var matchingWorkshop = j;
                workshops.splice(j, 1);
                selectedWorkshops.splice(i, 1);
            }
        }
    }
};
flipWorkshops();

按照 jwatts1980 的建议修复了拼接,反转了循环,将 selectedWorkshop 变量移出循环,并比较每个对象项,而不是比较对象,因为 objects don't compare .

JSFiddle Tweaked

JSFiddle Object Compare Example

关于javascript - 基于For循环迭代的数组拼接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29638527/

相关文章:

javascript - 如何循环枚举值以在单选按钮中显示?

javascript - 单击加载不同的 api 内容(JS)

javascript - 获取 javascript 对象中 key=option 的元素计数

html - 仅限 IE 的对象必需错误消息

javascript - 带连接的环回查询

c# - 如何在列表 C# MVC 中检索特定值

javascript - .clone 不是函数

javascript - 从 HTML 文件访问 JSON 文件以使用对象

javascript - 在浏览器调整大小时调整背景图像的大小

javascript - 使用 html 和 css 的 PDF 类型 View 。页面溢出问题