javascript - json 无法更改 dataWithLabels

Question

请您帮忙看一下代码。我想将标题名称从“Jason”更改为 JSON 文件中写入的温度。

var dataWithLabels = [
{
   "title":"Jason",  
}];

 $.ajax({
    url: "http://api.wunderground.com/api/2b38dcff93aa3dff/conditions/q/CA/Santa_Clara.json",
    type: "GET",
    dataType: "json", 
    success: function(data) {
    for(var i=0;i<1/*dataWithLabels.length*/;i++){
       var statistic = data.current_observation;
       dataWithLabels[i]['title']= statistic.temp_c;}} 
       //wanted to change Jason to the temperature written at the JSON file.Please help.
    });

 alert(dataWithLabels[0]['title']); 

http://codepen.io/wtang2/pen/bEGQKP

这不是重复的，我正在尝试将 JSON 文件的结果替换为 dataWithLabels 对象的标题

Answer 1

因为我不知道，如果您请求的 JSON 是正确的，我只是假设它是正确的。不过，如果您想了解 Ajax 请求之后 dataWithLabels 中发生了什么，您需要稍微重写该函数:

   var dataWithLabels = [{
    "title": "Jason",
  }];

  $.ajax({
    url:     "http://api.wunderground.com/api/2b38dcff93aa3dff/conditions/q/CA/Santa_Clara.json",
    type: "GET",
    dataType: "json",
    success: function(data) {
        for (var i = 0; i < 1 /*dataWithLabels.length*/ ; i++) {
          var statistic = data.current_observation;
          dataWithLabels[i]['title'] = statistic.temp_c;
          alert(dataWithLabels[i]['title']);
        }

      }
      //wanted to change Jason to the temperature written at the JSON  file.Please help.
  });

现在，在插入 statistic.temp_c 后，dataWithLabels 的状态就会发出警报。您的代码始终会在 Ajax 请求之前提醒状态。

希望有帮助!