我有一个 open
函数,一旦触发,只需在专用面板中播放视频即可。
此函数可以通过两种方式触发 - 一种通过点击,另一种通过页面加载(窗口加载)以及包含有效 anchor 标记的 url 来触发。
它们都工作正常,但窗口加载处理程序的一些代码是重复的,我不太确定如何保持这个干燥。
请看一下并给我指出一些方向,告诉我如何才能写得更好。
我在 open
函数中评论了它的用途。
$.videoWatch.prototype = {
init: function() {
this.$openLinks = this.$element.find(".open");
this.$closeLinks = this.$element.find(".close");
this.open();
this.close();
},
_getContent: function(element) {
var $parent = element.parent(),
id = element.attr('href').substring(1),
title = $parent.data('title'),
desc = $parent.data('desc');
return {
title: title,
desc: desc,
id: id
}
},
open: function() {
var self = this;
//open theatre with window load with #hash id
window.onload = function() {
var hash = location.hash;
var $a = $('a[href="' + hash + '"]'),
content = self._getContent($a),
$li = $a.parents("li"),
$theatreVideo = $(".playing"),
$theatreTitle = $(".theatre-title"),
$theatreText = $(".theatre-text");
$(".theatre").attr('id', content.id);
$theatreTitle.text(content.title);
$theatreText.text(content.desc);
if ($theatreText.text().length >= 90) {
$(".theatre-text").css({
'overflow': 'hidden',
'max-height': '90px',
});
$moreButton.insertAfter($theatreText);
}
$a.parent().addClass("active");
$(".theatre").insertAfter($li);
$(".theatre").slideDown('fast', scrollToTheatre);
oldIndex = $li.index();
}
//open theatre with click event
self.$openLinks.on("click", function(e) {
// e.preventDefault();
if (curID == $(this).parent().attr("id")) {
$("figure").removeClass("active");
$("button.more").remove();
$(".theatre").slideUp('fast');
$('.playing').attr("src", "");
removeHash();
oldIndex = -1;
curID = "";
return false
} else {
curID = $(this).parent().attr("id");
}
var $a = $(this),
content = self._getContent($a),
$li = $a.parents("li"),
$theatreVideo = $(".playing"),
$theatreTitle = $(".theatre-title"),
$theatreText = $(".theatre-text");
$(".theatre").attr('id', content.id);
$theatreTitle.text(content.title);
$theatreText.text(content.desc);
if ($theatreText.text().length >= 90) {
$(".theatre-text").css({
'overflow': 'hidden',
'max-height': '90px',
});
$moreButton.insertAfter($theatreText);
}
if (!($li.index() == oldIndex)) {
$("figure").removeClass("active");
$(".theatre").hide(function(){
$a.parent().addClass("active");
$(".theatre").insertAfter($li);
$(".theatre").slideDown('fast', scrollToTheatre);
oldIndex = $li.index();
});
} else {
$(".theatre").insertAfter($li);
scrollToTheatre();
$("figure").removeClass("active");
$a.parent().addClass("active");
}
});
},
...
最佳答案
简化和重构的open
方法:
open: function() {
var self = this;
var serviceObj = {
theatreVideo : $(".playing"),
theatre: $(".theatre"),
theatreTitle : $(".theatre-title"),
theatreText : $(".theatre-text"),
setTheatreContent: function(content){
this.theatre.attr('id', content.id);
this.theatreTitle.text(content.title);
this.theatreText.text(content.desc);
if (this.theatreText.text().length >= 90) {
this.theatreText.css({
'overflow': 'hidden',
'max-height': '90px',
});
$moreButton.insertAfter(this.theatreText);
}
},
activateTeatre: function(a, li){
a.parent().addClass("active");
this.theatre.insertAfter(li);
this.theatre.slideDown('fast', scrollToTheatre);
oldIndex = li.index();
}
};
//open theatre with window load with #hash id
window.onload = function() {
var hash = location.hash;
var $a = $('a[href="' + hash + '"]'),
content = self._getContent($a),
$li = $a.parents("li");
serviceObj.setTheatreContent(content);
serviceObj.activateTeatre($a, $li);
}
//open theatre with click event
self.$openLinks.on("click", function(e) {
// e.preventDefault();
if (curID == $(this).parent().attr("id")) {
$("figure").removeClass("active");
$("button.more").remove();
$(".theatre").slideUp('fast');
$('.playing').attr("src", "");
removeHash();
oldIndex = -1;
curID = "";
return false
} else {
curID = $(this).parent().attr("id");
}
var $a = $(this),
content = self._getContent($a),
$li = $a.parents("li");
serviceObj.setTheatreContent(content);
if (!($li.index() == oldIndex)) {
$("figure").removeClass("active");
$(".theatre").hide(function(){
serviceObj.activateTeatre($a, $li);
});
} else {
$(".theatre").insertAfter($li);
scrollToTheatre();
$("figure").removeClass("active");
$a.parent().addClass("active");
}
});
},
关于javascript - 重构 JavaScript 原型(prototype)构造函数中的重复代码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34982432/