我想访问一个棘手的 href。我无法硬编码这个 URL，因为它是由页面生成的，我将使用这个程序几年:
基类
https://gist.github.com/codyc4321/724f05aca8f6775e2fc1 (感兴趣的access_link)
class HCCDriver(FirefoxDriver):
def __init__(self, username="cchilders", password="mypw"):
super(HCCDriver, self).__init__(username=username, password=password, start_url="https://hccadvisor.hccfl.edu")
self.username = username
self.password = password
def login_testout(self):
driver = ChromeDriver()
driver.get("http://www.testout.com/")
login_a_tag = driver.access_link("hLogin")
我想要 StartLogin() 生成的内容:
<a id="hLogin" class="blue-button" href="javascript:StartLogin();" style="margin: 0 0 0 8px; border-right: 0; float: none; vertical-align: middle">Login</a>
错误:
In [3]: h.login_testout()
---------------------------------------------------------------------------
WebDriverException Traceback (most recent call last)
<ipython-input-3-3c353756ce70> in <module>()
----> 1 h.login_testout()
/home/cchilders/scripts/my_scripting_library/webdriver/specific.py in login_testout(self)
119 driver = ChromeDriver()
120 driver.get("http://www.testout.com/")
--> 121 login_a_tag = driver.access_link("hLogin")
122
123 def access_class_search_screen_hcc(self, category="CTS", driver=None):
/home/cchilders/scripts/my_scripting_library/webdriver/general.pyc in access_link(self, search_text)
89 element = self.locate_element(search_text)
90 link = element.get_attribute('href')
---> 91 self.get(link)
92
93 def submit_form(self, search_text=None):
/home/cchilders/scripts/my_scripting_library/webdriver/general.pyc in get(self, url)
64
65 def get(self, url=None):
---> 66 self.driver.get(url)
67
68 @property
/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.pyc in get(self, url)
211 Loads a web page in the current browser session.
212 """
--> 213 self.execute(Command.GET, {'url': url})
214
215 @property
/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.pyc in execute(self, driver_command, params)
199 response = self.command_executor.execute(driver_command, params)
200 if response:
--> 201 self.error_handler.check_response(response)
202 response['value'] = self._unwrap_value(
203 response.get('value', None))
/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/errorhandler.pyc in check_response(self, response)
192 elif exception_class == UnexpectedAlertPresentException and 'alert' in value:
193 raise exception_class(message, screen, stacktrace, value['alert'].get('text'))
--> 194 raise exception_class(message, screen, stacktrace)
195
196 def _value_or_default(self, obj, key, default):
WebDriverException: Message: unknown error: unsupported protocol
(Session info: chrome=48.0.2564.109)
(Driver info: chromedriver=2.9.248304,platform=Linux 3.19.0-15-generic x86_64)
最糟糕的是，代码的工作方式就像我使用 FirefoxDriver 一样，出于显而易见的原因，我更喜欢使用 chrome 来做作业。 chrome 可以访问这个链接吗？谢谢
最佳答案
您还可以单击链接并获取.current_url :
element = self.locate_element(search_text)
element.click()
link = self.driver.current_url
关于javascript - 访问从 javascript 函数 webdriver 动态生成的 href，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/35497324/