我有这样的 View 和减少: map :
function(doc) {
if(doc.type){
var usersLength = doc.users.length;
for (var i = 0; i < usersLength ; i++) {
emit([doc.users[i].userid,doc.Service.ownId], 1);
}
}
}
减少:
function(keys, values, rereduce)
{
return sum(values);
}
然后像这样调用 View :_design/aaa/_view/getUserId?group=true&group_level=2&startkey=["111111"]&endkey=["111111",{}]
我可以得到下面的结果集:
{"rows":[
{"key":["111111",""],"value":7},
{"key":["111111","FFFF26"],"value":1},
{"key":["111111","FFFF44"],"value":7},
{"key":["111111","FFFF34"],"value":2}
]}
但是,我希望将上面的结果集按照“value”值的降序排序。如果也使用列表功能可以实现吗?预期结果如下:
{"rows":[
{"key":["111111",""],"value":7},
{"key":["111111","FFFF44"],"value":7},
{"key":["111111","FFFF34"],"value":2},
{"key":["111111","FFFF26"],"value":1}
]}
最佳答案
如果您想对结果集进行排序,则必须按值降序排序,您可以使用比较器回调进行排序:
// ES6 Syntax
let originalResult = {
"rows":[
{"key":["111111",""],"value":7},
{"key":["111111","FFFF26"],"value":1},
{"key":["111111","FFFF44"],"value":7},
{"key":["111111","FFFF34"],"value":2}
]}
let newResult = {
rows: originalResult.rows.sort((a, b) => b.value - a.value)
}
关于javascript - 如何获得按 "value"值降序排序的映射/归约结果?如果也使用列表函数可以实现这一点?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38800308/