javascript - 如何遍历 HTML

Question

我有一个带有 HTML 代码的变量:

let htmlDocument = '<div id="buildings-wrapper"> \
    <div id="building-info"> \
    <h2><span class="field-content">Britney Spears' House</span></h2> \
    <div class="building-field"> \
    <div class="field-content">9999 Hollywood Blvd</div> \
    </div> \
    <div class="building-field"> \
    <div class="field-content">Building Hours: Mon. 07:00-23:00 Tue.-Fri. 06:30-22:00, Sat. 07:30-18:00, Sun. 12:00-18:00 Holidays - Closed</div> \
    </div> \
    <div class="building-field"> \
    <div class="field-content"><a href="http://www.britneyspears.com">Locate on the stars map</a></div> \
    </div> \
    </div> \
    <div id="building-image"> \
    <div class="field-content"><img src="../../../../ssc.adm.britneyspears.com/classroomservices/image/viewimage?userEvent=ShowBuildingImage&amp;buildingID=britneyspears" alt="Image of BritneySpears"></div> \
        </div> \
        </div>';

我想遍历该变量并将这部分 HTML 存储在单独的变量中:

<div class="field-content">9999 Hollywood Blvd</div>

这是我到目前为止所拥有的:

public traverseHTML(htmlDocument: any): any {
    let htmlBlock: any;
    let divs: any = htmlDocument.getElementsByTagName('div');
    for (var i = 0; i < divs.length; i++) {
        if (divs[i].getAttribute("id") == "field-content") {
            htmlBlock = divs[i];
        }
    }
    return htmlBlock;
}

我确信我的函数存在各种各样的问题，但我无法解决它们，因为我什至无法越过第二行。我收到一条错误消息，指出 htmlDocument.getElementsByTagName 不是函数。如何通过 div 迭代 HTML？

请注意，由于项目规范，我无法使用 JQuery。

编辑:

当我尝试document.createElement('div')时，我收到document is not Define，并且当我尝试创建 DOMParser 时，DOMParser is not Defined。我是否错误地设置了类(class)？这是整个类的代码:

import parse5 = require('parse5');
import {ASTNode} from 'parse5';



export default class DSController {
//private parser: DOMParser;

constructor() {
    //this.parser = new DOMParser();
}

public traverseHTML(htmlDocument: any): any {
    let parser = new DOMParser();
    let parsed: any = parser.parseFromString(htmlDocument, "text/html");
    let selectParsed: any = parsed.querySelectorAll('field-content')[1];
    console.log(selectParsed);

    return selectParsed;

   /* let element = document.createElement("div");
    element.innerHTML = htmlDocument;
    console.log(element.querySelectorAll(".field-content")[1]); // <div class="field-content">9999 Hollywood Blvd</div>
    */
}




public parseHTML(): any {

    //let document: parse5.ASTNode;
    return;
}
}

Answer 1

您可以创建一个元素，然后将此字符串作为 html 插入其中。
然后您可以查询此元素以获取您要查找的内容:

let htmlDocument = '<div id="buildings-wrapper"> \
    <div id="building-info"> \
    <h2><span class="field-content">Britney Spears House</span></h2> \
    <div class="building-field"> \
    <div class="field-content">9999 Hollywood Blvd</div> \
    </div> \
    <div class="building-field"> \
    <div class="field-content">Building Hours: Mon. 07:00-23:00 Tue.-Fri. 06:30-22:00, Sat. 07:30-18:00, Sun. 12:00-18:00 Holidays - Closed</div> \
    </div> \
    <div class="building-field"> \
    <div class="field-content"><a href="http://www.britneyspears.com">Locate on the stars map</a></div> \
    </div> \
    </div> \
    <div id="building-image"> \
    <div class="field-content"><img src="../../../../ssc.adm.britneyspears.com/classroomservices/image/viewimage?userEvent=ShowBuildingImage&amp;buildingID=britneyspears" alt="Image of BritneySpears"></div> \
        </div> \
        </div>';

let element = document.createElement("div");
element.innerHTML = htmlDocument;

console.log(element.querySelectorAll(".field-content")[1]); // <div class="field-content">9999 Hollywood Blvd</div>

( code in playground )