我正在尝试创建一个每 1 秒更新一次的计数器。我制作了一个每 30 秒返回一次的后端函数,它是通过 Ajax 调用的。调用结果除以 30,然后应在 30 秒内每 1 秒更新一次计数器。我该如何在 for 循环中添加 sleep ?
这是我到目前为止的代码:
function getCount() {
$.ajax({
url: '@Url.Action("", "", new {area = ""})',
type: 'POST',
success: function (data) {
var newTotalCount = data.totalCount;
var newDanishCount = data.danishCount;
var newNorwayCount = data.norwayCount;
var newSwedenCount = data.swedenCount;
var newUsCount = data.usCount;
var currentTotalCount = $("#odoTotal").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
var currentDanishCount = $("#odoDk").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
var currentNorwayCount = $("#odoNo").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
var currentSwedenCount = $("#odoSe").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
var currentUsCount = $("#odoUs").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
var updateTotalCount = newTotalCount - currentTotalCount;
var updateDanishCount = newDanishCount - currentDanishCount;
var updateNorwayCount = newNorwayCount - currentNorwayCount;
var updateSwedenCount = newSwedenCount - currentSwedenCount;
var updateUsCount = newUsCount - currentUsCount;
var updateTotalPerSecond = updateTotalCount / 30;
var updateDanishPerSecond = updateDanishCount / 30;
var updateNorwayPerSecond = updateNorwayCount / 30;
var updateSwedenPerSecond = updateSwedenCount / 30;
var updateUsPerSecond = updateUsCount / 30;
getAllSales();
for (var i = 0; i < 30; i++) {
window.setTimeout(function() {
$("#odoTotal").html(currentTotalCount+updateTotalPerSecond);
$("#odoDk").html(currentDanishCount+updateDanishPerSecond);
$("#odoNo").html(currentNorwayCount+updateNorwayPerSecond);
$("#odoSe").html(currentSwedenCount+updateSwedenPerSecond);
$("#odoUs").html(currentUsCount+updateUsPerSecond);
currentTotalCount = $("#odoTotal").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
currentDanishCount = $("#odoDk").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
currentNorwayCount = $("#odoNo").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
currentSwedenCount = $("#odoSe").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
currentUsCount = $("#odoUs").text().replace(/,/g, "").replace(/(\r\n|\n|\r)/gm, "");
}, 1000);
}
}
});
}
最佳答案
我有一个解决方案
首先创建一个要递增的变量
var x = 0;
然后创建一个间隔,该间隔将在时间结束后执行您想要的操作,例如 5(s),这也会在每次运行时增加您的值 x
var interval = setInterval(function() {
if (x >= 5) { // just change 5 to 30
console.log('Loop timeout ended');
return clearInterval(interval);
}
// do what ever you want
console.log('Current x: '+x);
x++;
}, 5000);
示例函数
function runTimeoutLoop(){
var x = 0;
var interval = setInterval(function() {
if (x >= 5) { // just change 5 to 30
console.log('Loop timeout ended');
return clearInterval(interval);
}
// do what ever you want
console.log('Current x: '+x);
x++;
}, 5000);
}
关于javascript - 在 JavaScript for 循环中休眠,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41297730/