java - 猜一个数字

Question

我想创建一个程序，让您尝试三次来找到任何给定的数字。这本质上是一个猜谜游戏。问题是，我必须在没有任何循环的情况下执行此操作。到目前为止，我只能从用户那里获取输入，读取该输入并告诉他们是赢了还是“输了”游戏。该程序仅运行一次并停止(如预期)。

有人告诉我，尽管需要更多代码，但无需循环即可完成。你们能让我知道我在这里做错了什么，并给我一些关于我应该改变什么的指示吗？如果您需要澄清，请告诉我。 谢谢。

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {

        Scanner ran = new Scanner(System.in);
        System.out.println("Enter a number: ");
        int x = ran.nextInt();

        if (x < 3) {
            System.out.println("Too low. Try again.");

            System.out.println("Enter a number: ");
        } else if (x > 3) {
            System.out.println("Too high. Try again");

        } else if(x == 3) {
            System.out.println("You win. Nice job.");
        } else {
            System.out.println("You lose");
        }

        System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
    }
}

Answer 1

您可以使用递归来完成此操作。看看这个程序。在评论中查找解释。

import java.util.Scanner;

public class HelloWorld {

    private static Scanner ran = new Scanner(System.in);

    //this is number of tries you want to give to user
    private static int counter = 5;

    //The actual number
    private static final int NUM = 3;

    public static boolean guessingMachine() {
        //counter indicates that number of attempts remaining
        if(counter == 0) {
            return false;
        }
        counter--;

        System.out.println("Enter a number: ");
        int x = ran.nextInt();

        if (x < NUM) {
            System.out.println("Too low. Try again.");
            //try again... call this method again
            return guessingMachine();
        } else if (x > NUM) {
            System.out.println("Too high. Try again");
            //try again... call this method again
            return guessingMachine();
        } else {
            //x == NUM success
            return true;
        }
    }


    public static void main(String[] args) {
        boolean result = guessingMachine();

        if(result) 
            System.out.println("You win. Nice job.");
        else 
            System.out.println("You lose");

        System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
    }
}