java - 未找到变量结果

Question

程序非常简单，而且是自布置的，所以不，这不是作业。

用户应该输入三个数字，显示数字的平方并显示数字的总和。

import java.util.Scanner;
public class CompSquares {
    public static void main (String args[]) {
        Scanner s= new Scanner( System.in); 
        int num1;
        System.out.println(" Enter a number please.");
        num1 = s.nextInt();
        int num2;
        System.out.println("One more."); 
        num2 = s.nextInt();
        int num3;
        System.out.println("Last one.");
        num3 = s.nextInt();

        System.out.println( "The numbers squared are " + Square( num1, num2, num3));
        System.out.println("The sum of these numbers is " + Sum(result)); 
    }

    private static double Square ( int num1, int num2, int num3) {

        if ( num1 > 0) {
            num1 *= num1;
            System.out.println (num1);} 
            else {
                System.out.println( "Enter a correct number, please.");
            }
            if ( num2 > 0){ 
                 num2 *= num2;
                System.out.println (num2); }
                else {
                    System.out.println("Really? Again. Do the right thing this time, jeez.");
                }
            if ( num3 > 0){
                num3*=num3;
                System.out.println (num3);}
                else {
                    System.out.println("Just make it more then one!!");
                }
            }

    public static int Sum ( int num1, int num2, int num3, int result) {
        result = num1 + num2 + num3;
        System.out.println(result);
    }
}            

Answer 1

在主方法中:

 System.out.println("The sum of these numbers is " + Sum(result)); 

result尚未在 main() 可见的任何范围内声明.

而不是 Sum采取int result参数，我认为你的意思是 Sum至return结果。在不给您完整答案的情况下，从这里开始:

public static int Sum (int num1, int num2, int num3) {
    int result = num1 + num2 + num3;
    System.out.println(result);
    return result;
}

这还将解决另一个编译器错误(原始代码中的 Sum 不会返回任何内容，但它声明的返回类型是 int )。