构造函数中的 Java 条件以调用父构造函数

Question

我有一个以下 Java 类:

public class CharacteristicResponse extends VotableResponse {

    public CharacteristicResponse() {
    }

    public CharacteristicResponse(Characteristic characteristic) {
        super(characteristic);

        this.characteristicId = characteristic.getId();
        this.name = characteristic.getName();
        this.nameSlug = characteristic.getNameSlug();
        this.description = characteristic.getDescription();
        this.valueType = characteristic.getValueType();
        this.visualMode = characteristic.getVisualMode();

        ...

    }

}

我想向构造函数添加额外的参数，以便能够控制 super 构造函数调用..例如如下所示:

public CharacteristicResponse(Characteristic characteristic, Boolean detailed) {
    if(detailed) {
        super(characteristic);
    }
...

}

从 Java 的角度来看，上面的示例是不可能的，因此我正在寻找一种解决方案，如何以其他方式完成它。

Answer 1

您在评论中说过:

Currently I have a pretty deep chain of a nested super calls.. so I was wondering there is an elegant way how it can be done with no needs to rewrite a lot of code..

为了不让情况发生太大变化，我基本上看到了三个选择:

1. 在 detailed 为 false 且具有 VotableResponse(Characteristic) 的情况下，您可以传递 null处理获取null:

   super(detailed ? characteristic : null);
   

2. 如果 detailed 为 true，您始终可以调用 super()，然后立即通过 setter 设置characteristic。

   super();
   if (detailed) {
       super.setCharacteristic(characteristic);
   }
   

3. 您可以将标志传递到链上，并让沿途的每个类适本地处理它。