我正在尝试播放用户选择的文件夹中的歌曲。本质上,我正在使用我自己创建的队列,并且我得到了正确的路径。
在下面的代码中,我使用了一个名为 path 的 Var。路径是“C:\Users\Shaun\Downloads\TestMusic\Ed Sheeran - Shape of You.mp3”。当我将路径定义为“Ed Sheeran - Shape of You.mp3”时。有用!这告诉我,这会查看项目启动或运行的目录。
那么,如何让它播放任何给定目录中的文件?
我指的“路径”如下,“public void handlecentreButtonClick()”。
public class graphicalController implements Initializable
{
//GUI Decleration
public Button centreButton;
public Button backButton;
public Button forwardButton;
public ToggleButton muteToggle;
public MenuItem loadFolder;
//Controller Decleration
String absolutePath;
SongQueue q = new SongQueue();
MediaPlayer player;
@Override
public void initialize(URL location, ResourceBundle resources)
{
centreButton.setStyle("-fx-background-image: url('/Resources/Play_Button.png')");
centreButton.setText("");
backButton.setStyle("-fx-background-image: url('/Resources/Back_Button.png')");
backButton.setText("");
forwardButton.setStyle("-fx-background-image: url('/Resources/Forward_Button.png')");
forwardButton.setText("");
muteToggle.setStyle("-fx-background-image: url('/Resources/ToggleSound_Button.png')");
muteToggle.setText("");
}
public void handlecentreButtonClick() {
if(!(q.isEmpty())) {
String file = q.peek().fileName.toString();
String path = absolutePath + "\\" + file;
Media song = new Media(path);
player = new MediaPlayer(song);
player.play();
}
}
public void handleforwardButtonClick() {
System.out.println("Hello.");
centreButton.setText("Hello");
}
public void handlebackButtonClick() {
System.out.println("Hello.");
centreButton.setText("Hello");
}
public void handleLoadButtonClick() {
DirectoryChooser directoryChooser = new DirectoryChooser();
File selectedDirectory = directoryChooser.showDialog(null);
absolutePath = selectedDirectory.getAbsolutePath();
String path = absolutePath;
loadFilesFromFolder(path);
}
public void loadFilesFromFolder(String path) {
File folder = new File(path);
File[] listOfFiles = folder.listFiles();
while(!(q.isEmpty()))
{
try {Thread.sleep(500);}catch (Exception e){}
Song j = q.pop();
}
int listLength = listOfFiles.length;
for (int k = 0; k < listLength; k++) {
if (listOfFiles[k].isFile()) {
String fileName = listOfFiles[k].getName();
String fileNamePath = path + "\\" +fileName;
try {
InputStream input = new FileInputStream(new File(fileNamePath));
ContentHandler handler = new DefaultHandler();
Metadata metadata = new Metadata();
Parser parser = new Mp3Parser();
ParseContext parseCtx = new ParseContext();
parser.parse(input, handler, metadata, parseCtx);
input.close();
String songName = metadata.get("title");
String artistName = metadata.get("xmpDM:artist");
String albumName = metadata.get("xmpDM:genre");
int id = k + 1;
Song newSong = new Song(id, fileName, songName, artistName, albumName);
q.push(newSong);
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
} catch (TikaException e) {
e.printStackTrace();
}
}
}
}
}
最佳答案
使用
Media song = new Media(new File(path).toURI().toString());
但是,我强烈建议您以独立于平台的方式构建文件,而不是硬编码特定于某个特定文件系统的文件分隔符。你可以做
File path = new File(absolutePath, file);
Media song = new Media(path.toURI().toString());
关于java - 播放所选目录中的 MP3 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43620506/