java - 将图像从 url 添加到 viewpager 的第二和第三位置

Question

这里我有两个网址，但是当我运行这个应用程序时，这些图像被加载到第二页意味着第一张图像将在几秒钟后加载到第二页中，第二张图像也会通过重叠添加到相同的位置。我需要将其添加到第二页和第三页这些网址

 viewPager = (ViewPager) findViewById(R.id.splash);
        ImageAdapter adapter = new ImageAdapter(this);
        viewPager.setAdapter(adapter);

public class ImageAdapter extends PagerAdapter {

        Context context;

        private int[] GalImages = new int[] {
                R.drawable.slider,
                R.drawable.slider,
                R.drawable.slider,
        };

        ImageAdapter(Context context){
            this.context=context;
        }

        @Override
        public int getCount() {
         return GalImages.length;
         //   return 10;
        }

        @Override
        public boolean isViewFromObject(View view, Object object) {
            return view == ((ImageView) object);
        }

        @Override
        public Object instantiateItem(ViewGroup container, int position) {
            ImageView imageView = new ImageView(context);
            imageView.setScaleType(ImageView.ScaleType.FIT_XY);
            imageView.setImageResource(GalImages[position]);
            new LoadImage(imageView).execute("http://www.gadgetbaazar.com/wp-content/uploads/2016/12/Top-Mobile-Phones.jpg");
            new LoadImage(imageView).execute("https://pisces.bbystatic.com/BestBuy_US/store/ee/2015/com/pm/nav_desktops_1115.jpg");
            container.addView(imageView, 0);
            return imageView;
        }

        @Override
        public void destroyItem(ViewGroup container, int position, Object object) {
            ((ViewPager) container).removeView((ImageView) object);
        }



        private class LoadImage extends AsyncTask<String, String, Bitmap> {
            ImageView img=null;
            public LoadImage(ImageView img){
                this.img=img;
            }
            @Override
            protected void onPreExecute() {
                super.onPreExecute();

            }
            protected Bitmap doInBackground(String... args) {
                Bitmap bitmap=null;
                try {
                    bitmap = BitmapFactory.decodeStream((InputStream)new URL(args[0]).getContent());
                } catch (Exception e) {
                    e.printStackTrace();
                }
                return bitmap;
            }
            protected void onPostExecute(Bitmap image) {
                if(image != null){
                    img.setImageBitmap(image);
                }
            }
        }
    }

Answer 1

试试这个

@Override
        public Object instantiateItem(ViewGroup container, int position) {
            ImageView imageView = new ImageView(context);
            imageView.setScaleType(ImageView.ScaleType.FIT_XY);
            if(position == 0){
            imageView.setImageResource(GalImages[position]);
            }else if(position == 1){
            new LoadImage(imageView).execute("http://www.gadgetbaazar.com/wp-content/uploads/2016/12/Top-Mobile-Phones.jpg");
            }else if(position ==2){
            new LoadImage(imageView).execute("https://pisces.bbystatic.com/BestBuy_US/store/ee/2015/com/pm/nav_desktops_1115.jpg");
            }

            container.addView(imageView, 0);
            return imageView;
        }