我有一个入门级问题:
如果有外部java类，假设该类中有一个名为“method1”的方法，该方法内有一个名为“method1”的方法，该方法内有一个覆盖方法“onResponse”，两个变量被设置为“a”和“b” .
在 android mainActivity 中，我从类中调用了该方法，如下所示:
Class1.method1();
调用该方法后，我如何检索这些变量以在 mainActivity 中使用...
谢谢..
public abstract class Class1 extends Context {
final Context mcontext;
public static void method1(final Context mcontext, final String x){
StringRequest stringRequest = new StringRequest(Request.Method.POST, constants.URL, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject parentObject = new JSONObject(response);
JSONObject userDetails = parentObject.getJSONObject("data");
//read attributes
String a = userDetails.getString("a");
String b = userDetails.getString("b");
} catch (JSONException e) {
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(mcontext, error.getMessage() ,Toast.LENGTH_LONG).show();
}
}){
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String,String> params = new HashMap<>();
params.put("x", x);
return params;
}
};
requestHandler.getInstance(mcontext).addToRequestQueue(stringRequest);
}
最佳答案
为什么不为 a 和 b 创建包装类
public class Details {
public string a;
public string b;
}
然后在方法1中读取/返回它
public abstract class Class1 extends Context {
final Context mcontext;
public static Details method1(final Context mcontext, final String x){
Details data = new Details;
StringRequest stringRequest = new StringRequest(Request.Method.POST, constants.URL, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject parentObject = new JSONObject(response);
JSONObject userDetails = parentObject.getJSONObject("data");
//read attributes
data.a = userDetails.getString("a");
data.b = userDetails.getString("b");
} catch (JSONException e) {
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(mcontext, error.getMessage() ,Toast.LENGTH_LONG).show();
}
}){
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String,String> params = new HashMap<>();
params.put("x", x);
return params;
}
};
requestHandler.getInstance(mcontext).addToRequestQueue(stringRequest);
return data;
}
关于java - 使用来自 java 类和方法的数据，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/44445288/