java - 如何使单个按钮在 Android 中显示为 Activity 状态

Question

我学习java有一段时间了，正在开发一个Android应用程序。我正在尝试为嵌套在线性布局中的图像按钮实现一种 boolean 逻辑，其中只有一个按钮应该显示 Activity 按钮，而其他按钮则不显示。 目前，每个按钮都可以在 Activity 和非 Activity 之间切换，但我不希望有两个以上按钮同时显示 Activity 状态。我想要一个一次显示一个 Activity 按钮的按钮。

 public void showAudio(View view) {
        if (!audioButtonClicked) {
            audioButtonClicked = true;
            audioWindowButton.setImageResource(R.drawable.audio_active);
        } else {
            audioWindowButton.setImageResource(R.drawable.audio_inactive);
            audioButtonClicked = false;
        }

        }

    public void showEvents(View view) {
       if(!eventButtonClicked ) {
eventWindowButton.setImageResource(R.drawable.event_active);
           eventButtonClicked = true;
       } else {
           eventWindowButton.setImageResource(R.drawable.event_inactive);
           eventButtonClicked = false;
       }
    }

    public void showMore(View view) {
        if(!moreButtonClicked) {
            moreWindowButton.setImageResource(R.drawable.event_active);
            moreButtonClicked = true;

        } else {
            moreWindowButton.setImageResource(R.drawable.event_inactive);
            moreButtonClicked = false;
        }
    }

Answer 1

您可以使用button.setVisibility()更改其可见性。这是伪代码。

if() { // some condition when you want imageButton1 to be visibile and others invisible
    imageButton1.setVisibility(View.VISIBLE);     
    imageButton2.setVisibility(View.INVISIBLE);
    imageButton3.setVisibility(View.INVISIBLE);
} else if() { // some other condition when you want imageButton2 to be visibile and others invisible
    imageButton1.setVisibility(View.INVISIBLE);
    imageButton2.setVisibility(View.VISIBLE);
    imageButton3.setVisibility(View.INVISIBLE);
} else { // when you want imageButton3 to be visibile and others invisible
    imageButton1.setVisibility(View.INVISIBLE);
    imageButton2.setVisibility(View.INVISIBLE);
    imageButton3.setVisibility(View.VISIBLE);
}

使用上述逻辑:

public void showAudio(View view) {
        if (!audioButtonClicked) {
            audioButtonClicked = true;
            eventButtonClicked = false;
            moreButtonClicked = false;
            audioWindowButton.setImageResource(R.drawable.audio_active);
            eventWindowButton.setImageResource(R.drawable.event_inactive);
            moreWindowButton.setImageResource(R.drawable.event_inactive);
        } else {
            audioWindowButton.setImageResource(R.drawable.audio_inactive);
            audioButtonClicked = false;
        }
}

public void showEvents(View view) {
        if(!eventButtonClicked ) {
            audioButtonClicked = false;
            eventButtonClicked = true;
            moreButtonClicked = false;
            audioWindowButton.setImageResource(R.drawable.audio_inactive);
            eventWindowButton.setImageResource(R.drawable.event_active);
            moreWindowButton.setImageResource(R.drawable.event_inactive);
        } else {
           eventWindowButton.setImageResource(R.drawable.event_inactive);
           eventButtonClicked = false;
        }
}

public void showMore(View view) {
        if(!moreButtonClicked) {
            audioButtonClicked = false;
            eventButtonClicked = false;
            moreButtonClicked = true;
            audioWindowButton.setImageResource(R.drawable.audio_inactive);
            eventWindowButton.setImageResource(R.drawable.event_inactive);
            moreWindowButton.setImageResource(R.drawable.event_active);

        } else {
            moreWindowButton.setImageResource(R.drawable.event_inactive);
            moreButtonClicked = false;
        }
}

仅当功能启用而其他功能禁用时才会显示。如果启用其中任何一项功能，则其他两项功能将被禁用，但如果仅禁用一项功能，则其他功能不会更改。