java - 响应未设置状态 400 Jersey

Question

我的 API 上有下面的代码，如果用户在我的数据库中，它会发回。当用户不在我的数据库中时，我会尝试让它返回错误 400，但是当我使用其他代码对其发出请求时下面，状态为200

@POST
@Path("/login")
@Consumes("application/json; charset=UTF-8")
@Produces("application/json; charset=UTF-8")
public HashMap<String, Object> login(User userLogin) {
    User user;
    HashMap<String, Object> responsed = new HashMap<>();
    try {

        user = userBO.userExists(userLogin);


        request.getSession().setAttribute("user", user);

        logger.debug("User inserido na session: " + new Date() + " - " + user.toString());
        logger.debug("Session LOGIN: " + new Date() + " - " + request.getSession().hashCode());

        responsed.put("logado", true);
        responsed.put("status",200);

    } catch (Exception e) {
        response.setStatus(Response.Status.BAD_REQUEST.getStatusCode());
        responsed.put("logado", false);
        responsed.put("status",400);
    }

    return responsed;
}

这是回复

   @Context 
   private HttpServletResponse response;

这是提出申请的客户端；

   angular.module('app').controller('loginController', function($scope, $location, $http) {

 $scope.bruno = () =>{
  $http.post('http://localhost:8080/modeloAPI/auth/login', $scope.user)
  .then(function(response) {
    console.log('deu bom');
    console.log(response);
      $location.path('/dashboard');
  })
  .catch(function(response) {
    console.log('deu ruim');
  });
  }

 });

当状态为 400 时，它不应该更改页面，但它确实如此

page return

Answer 1

设置状态后需要调用flushBuffer()方法:

Forces any content in the buffer to be written to the client. A call to this method automatically commits the response, meaning the status code and headers will be written.

— ServletResponse.flushBuffer() method (Java(TM) EE 7 Specification APIs).

例如如下:

...
HttpServletResponse response;
...

response.setStatus(HttpServletResponse.SC_BAD_GATEWAY);
response.flushBuffer();

有用的相关问题:JAX-RS — How to return JSON and HTTP status code together? .

希望这有帮助。