java - 表名是什么？

Question

我正在使用 H2 数据库创建 Spring Boot 应用程序。我不断收到以下错误:

Table "THINGS_TO_DO" not found; SQL statement:
insert into things_to_do (id, name, verified) values (1, 'TestUser1', 1) [42102-197]

而且，我觉得这是合乎逻辑的，因为我不知道在应用程序中在哪里传递这个表名称。另外，表名称应该是什么 - 表必须有一些特定的名称吗？

My ThingsToDo.java 如下所示:

package me.hiboy.springboot.microservice.example.todo;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name="things_to_do")
public class ThingsToDo {

    @Id
    private Long id;

    @Column(name="name")
    private String name;

    @Column(name="verified")
    private int verificationStatus;

    private String task;

    public ThingsToDo() {

    }

    public ThingsToDo(Long id, String name, int verificationStatus, String task) {
        super();
        this.id=id;
        this.name=name;
        this.verificationStatus=verificationStatus;
        this.task=task;
    }

    public Long getId() {
        return id;
    }

    public String getName() {
        return name;
    }

    public int getVerificationStatus() {
        return verificationStatus;
    }

    public String getTask() {
        return task;
    }
}

Controller ThingsToDoController.java如下:

package me.hiboy.springboot.microservice.example.todo;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RestController;

@RestController
public class ThingsToDoController {

    @Autowired
    ThingsToDoRepository repository;

    @GetMapping("/")
    public String index() {
        return "Hello from the ToDo Controller\n";
    }

    @GetMapping("/todo/{name}")
    public ThingsToDo getThingsToDo(@PathVariable String name) {
        ThingsToDo thingToDo=repository.findByName(name);

        return thingToDo;
    }
}

存储库 ThingsToDoRepository 是:

package me.hiboy.springboot.microservice.example.todo;

import org.springframework.data.jpa.repository.JpaRepository;

public interface ThingsToDoRepository extends JpaRepository<ThingsToDo, Long> {
    ThingsToDo findByName(String name);
}

Application.properties 是:

spring.application.name=todo-service
server.port=8080
spring.jpa.show-sql=true
spring.h2.console.enabled=true
spring.datasource.url=jdbc:h2:mem:mydb;DB_CLOSE_DELAY=-1;DB_CLOSE_ON_EXIT=FALSE
spring.datasource.username=sa
spring.datasource.password=
spring.datasource.driverClassName=org.h2.Driver
spring.datasource.platform=h2
spring.datasource.initialize=true

data.sql 是:

insert into things_to_do (id, name, verified) values (1, 'TestUser1', 1);
insert into things_to_do (id, name, verified) values (2, 'TestUser2', 0);

我认为 pom.xml 不是必需的 - 如果是的话，请让我知道，我也会发布它。谢谢。

编辑: 带有 main() 方法的那个在这里:

package me.hiboy.springboot.microservice.example.todo.springbootmicroservicetodoservice;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

@SpringBootApplication
public class SpringBootMicroserviceTodoServiceApplication {

    public static void main(String[] args) {
        SpringApplication.run(SpringBootMicroserviceTodoServiceApplication.class, args);
    }
}

编辑:到目前为止给出的所有答案都没有任何帮助。

Answer 1

按照包名称作为 如果您的主类位于 com.example 包中 那么你的应用程序中的所有包都将遵循这个包 对于新实体，包将是 com.example.entity