java - 从 @ResponseBody 返回 JSONArray 时抛出错误

Question

我使用 @Controller 通过 ActiveMQ 从 Elasticsearch 获取记录。但是，当我以 JSON 数组形式返回 ElasticSearch 响应时，我的 Postman 客户端中出现以下错误

请在下面找到我的错误。

{
"timestamp": "2018-06-09T06:59:18.755+0000",
"status": 500,
"error": "Internal Server Error",
"message": "Type definition error: [simple type, class org.json.JSONObject]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: No serializer found for class org.json.JSONObject and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS)",
"path": "/document/40011"
}

请找到我尝试返回 JSONArray 的 @Controller 方法

@RequestMapping(value = DOCUMENTS, method = RequestMethod.GET)
    public @ResponseBody JSONArray getDocumentByName(HttpServletRequest httpRequest, HttpServletResponse httpResponse, @PathVariable("name") String name) {
        System.out.println("Searching documents....");
        JSONArray result;
        result = searchEngineClient.searchByDocuments(name);
        return result;
    }

请找到堆栈跟踪:

com.fasterxml.jackson.databind.exc.InvalidDefinitionException: No serializer found for class org.json.JSONObject and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS)
at com.fasterxml.jackson.databind.exc.InvalidDefinitionException.from(InvalidDefinitionException.java:77) ~[jackson-databind-2.9.5.jar:2.9.5]
at com.fasterxml.jackson.databind.SerializerProvider.reportBadDefinition(SerializerProvider.java:1191) ~[jackson-databind-2.9.5.jar:2.9.5]
at com.fasterxml.jackson.databind.DatabindContext.reportBadDefinition(DatabindContext.java:312) ~[jackson-databind-2.9.5.jar:2.9.5]
at com.fasterxml.jackson.databind.ser.impl.UnknownSerializer.failForEmpty(UnknownSerializer.java:71) ~[jackson-databind-2.9.5.jar:2.9.5]

能够以 String 形式返回以下代码的响应。但我想以 JSONArray 形式返回。

@RequestMapping(value = DOCUMENTS, method = RequestMethod.GET)
public @ResponseBody Object getDocumentByName(HttpServletRequest httpRequest, HttpServletResponse httpResponse, @PathVariable("name") String name) {
    System.out.println("Searching documents....");
    JSONArray result;
    result = searchEngineClient.searchByDocuments(name);
    return result.toString();
}

Answer 1

只需删除@ResponseBody。如果这是一个 @RestController ，它将自动序列化为 JSON。