java - 创建相同方法名称的 2 个实现；一个来自@Override，另一个来自派生的

Question

我知道这个问题已经被问了一百万次，但我不太确定我有我需要的解决方案。这个问题很可能有“否”的答案，但我愿意接受这个问题的其他解决方案。

我正在实现我自己的 Exception 类，它是从另一个也实现了 Iterable 的类扩展而来的。

class TCBPackageException extends TCBRuntimeException implements Iterable<TCBRuntimeException> {

private List<TCBRuntimeException> exceptions = new LinkedList<>();

TCBPackageException(Throwable t) {
    super(t);
}

class TCBPackageIterator extends Iterator<TCBRuntimeException> {

    public boolean hasNext() {
        ...
    }
    public TCBRuntimeException next() {
        ...
    }
}

public void addException(TCBRuntimeException e) {
    exceptions.add(e);
}


//  Here's My ISSUE


// When getMessage() is Called on TCBPackageException I want the accumulation of all the messages stored.

@Override
public String getMessage() {
    StringBuffer buffer = new StringBuffer(super.getMessage());
    for (TCBException ex : exceptions) {
        buffer.append(ex.getMessage());
    }
    return buffer.toString();
}

// If I use an Iterator and end up getting this as the FIRST object, I just want the message of THIS exception.
public String getMessage() {
    return super.getMessage();
}

Answer 1

来自https://docs.oracle.com/javase/tutorial/java/javaOO/methods.html

The Java programming language supports overloading methods, and Java can distinguish between methods with different method signatures. This means that methods within a class can have the same name if they have different parameter lists (there are some qualifications to this that will be discussed in the lesson titled "Interfaces and Inheritance").

考虑到这一点，你不能定义两个具有绝对相同签名的方法(像@Override这样的注释不属于签名)。如果您定义两个没有任何区别的方法 getMessage()，编译器将不知道您试图通过 o.getMessage() 调用哪一个。

您必须以不同的方式命名它们或定义不同的参数集。建议:

@Override
public String getNestedMessages() {

    StringBuffer buffer = new StringBuffer(super.getMessage());

    for (TCBException ex : exceptions) {

        buffer.append(ex.getMessage());

    }

    return buffer.toString();

}

第二个方法 getMessage() 绝对已经过时了，因为如果您不重写它，您会自动从父类(super class)中调用它。