所以我正在编写一个比较盒子体积的程序...但我需要让它运行,以便不打印小于一的值并提示错误消息。 (即“第一个框是第二个框大小的 0.5 倍”或“第一个框是第二个框大小的 0 倍”)-- 相反,我希望它打印“错误:请输入大于的有效数字”大于 1"
这是我试图修复的代码部分:
if (volume1 == volume2) {
System.out.println("The first box is the same size as the second box");
}else if(volume1 >= 0 || volume2 >= 0){
System.out.println("Error. Please enter a valid number greater than 0");
}else {
String bigger = "first box";
String smaller = "second box";
double ratio = volume1 / volume2;
if (volume2 > volume1) {
bigger = "second box";
smaller = "first box";
ratio = volume2 / volume1;
}
String compare;
switch((int) ratio) {
case 1: compare = " is slightly bigger than ";
break;
case 2: compare = " is twice the size of ";
break;
case 3: compare = " is triple the size of ";
break;
case 4: compare = " is quadruple the size of ";
break;
default: compare = " is " + (int) ratio + " times the size of ";
break;
}
System.out.println("The " + bigger + compare + smaller);
}
我希望这是足够的代码来解释我的问题是什么。据我所知,我认为 switch 语句不能有条件,并且由于 int 比率的构造方式,当我测试它时,它会一直打印 0。有什么建议吗?
最佳答案
好的,我希望我正确回答了你的问题:) 那么你可以在默认分支中添加一点 if 语句:
// Here the Code till default
default:
if (ratio < 1) {
System.err.println("Error: Please enter a valid number greater than 1");
return; // You should consider to return out of the method here otherwise "The" still gets printed for no reason :)
} else compare = " is " + (int) ratio + " times the size of ";
}
// Rest of Code
这应该可以完成工作:)
关于java - 禁止程序输入小于1的数字(if else/switch),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53073497/