我正在获取用户输入的单词列表，并将其输入存储在 String[] 数组中。然后，我创建一个名为 letterGrid 的 char[][] 数组，其中填充了随机字母和用户提供的单词。当 letterGrid 显示在控制台屏幕上时，用户必须输入他们想要查找的单词。然后程序将检查输入的单词是否水平、垂直或对角显示，并打印出它的位置。我的 checkHorizontal 和 checkDiagonal 方法工作正常，但我在 checkVertical 时遇到问题。例如，我的单词示例输入是红色、橙色、黄色、绿色、蓝色、紫色、彩虹和颜色。下面是输出网格:
如您所见，当我输入黄色(长度为 6 个字母)时，程序会输出该单词的位置，但随后会出现越界错误。
编辑代码
以下是应 @Igor Khvostenkov 请求的其余代码:
private String word; // This variable will be the user`s input when they chose to search for a word they have entered
private int rowLocation; // This variable will represent the row number in which the word is at
private int colLocation; // This variable will represent the column number in which the word is at
// Create a method to compare the user`s word to the elements in the letter grid
public void compare (String word) {
for (int row = 0; row < letterGrid.length - 1; row++) {
for (int col = 0; col < letterGrid[row].length - 1; col++) {
if (letterGrid[row][col] == word.charAt(0)) {
rowLocation = row;
colLocation = col;
wordContains(); // Call on method to see if the word entered by the user appears horizontally, vertically, or diagonally
}//end of if
}//end of inner for loop
}//end of outer for loop
}//end of compare(word)
// Create a method that will check the direction of the user`s word input
public void wordContains() {
checkHorizontal(); // Checking if the word appears horizontally
checkVertical(); // Checking id the word appears vertically
checkDiagonal(); // Checking if the word appears diagonally
}//end of wordContains()
// Create a method to check if the user`s word appears HORIZONTALLY in the letter grid
public void checkHorizontal() {
for (int i = 1; i < (word.length()); i++) {
if (colLocation + i > letterGrid[0].length - 1) {
return;
} else if(letterGrid[rowLocation][colLocation + i] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found horizontally at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
return;
}//end of checkHorizontal()
// Create a method to check if the user`s word appears VERTICALLY in the letter grid
public void checkVertical() {
for (int i = 1; i < (word.length()); i++) {
if (rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length) {
return;
} else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
}//end of checkVertical()
// Create a method to check if the user`s word appears DIAGONALLY in the letter grid
public void checkDiagonal() {
for (int i = 1; i < (word.length()); i++) {
if (colLocation + i > letterGrid[0].length - 1 || rowLocation + i > letterGrid.length - 1) {
return;
} else if (letterGrid[rowLocation + i][colLocation + i] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found diagonally at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println("");
}//end of checkDiagonal()我似乎不知道为什么会发生这种情况，以及如何解决这个问题。我对 ArrayIndexOutofBounds 异常不太熟悉，因为我几乎没有经历过它们，但最近我一直在尝试理解这个问题并寻找帮助我解决它的方法。
最佳答案
代码中的问题在于 checkVertical() 中的 if 条件，行和列可以是第一个或最后一个，但您应该检查行或列。您的黄色示例失败，因为第一个代码在第一行和第二列中找到 Y ，然后继续扫描，最后，它在最后一行找到 Y 并检查 rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length 跳过，然后调用 else 向该行添加 1，结果输出绑定(bind)数组。这应该有效:
public void checkVertical() {
for (int i = 1; i < (word.length()); i++) {
if (rowLocation + i > letterGrid.length - 1 || colLocation + i > letterGrid[0].length) {
return;
} else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
}//end of checkVertical()
关于java - 如何在 Java 中对角检查 2D 字符数组中的字符串 (Eclipse)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54312474/