我使用此代码来运行 Spring 任务:
@Scheduled(fixedRate = 90000)
public void myScheduler() throws Exception {
ZonedDateTime zonedDateTime = ZonedDateTime.now(zone);
DateTimeFormatter format = DateTimeFormatter.ofPattern("MMM d yyyy hh:mm a");
String time = zonedDateTime.format(format);
System.out.printf("Scheduler exectuted (%s, (%s))\n", time, zone);
TaskLogs task = new TaskLogs();
task.setStatus("completed");
task.setCreatedAt(LocalDateTime.now());
task.setLog("Executing Notification Job");
task.setTask_name("Executing Notification Job at " + time + " (" + zone + ")");
taskLogsService.save(task);
}
但有时我会遇到 SQL 错误。拦截错误的最佳方法是什么?我应该使用经典的 try-catch block 还是有一个任务监听器?
最佳答案
我建议在运行 @Schedule 时使用 try catch 和 SQLException 是最好的选择 - 可能你不想破坏它,
@Scheduled(fixedRate = 90000)
public void myScheduler() throws SQLException {
ZonedDateTime zonedDateTime = ZonedDateTime.now(zone);
DateTimeFormatter format = DateTimeFormatter.ofPattern("MMM d yyyy hh:mm a");
String time = zonedDateTime.format(format);
System.out.printf("Scheduler exectuted (%s, (%s))\n", time, zone);
TaskLogs task = new TaskLogs();
task.setStatus("completed");
task.setCreatedAt(LocalDateTime.now());
task.setLog("Executing Notification Job");
task.setTask_name("Executing Notification Job at " + time + " (" + zone + ")");
try {
taskLogsService.save(task);
} catch (SQLException sqle){
System.out.println(sqle);
//or you can use slf4j logger to record same in logfile
}
}
关于java - 将异常捕获到 Spring Job 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55724615/