我是 Android 新手...我正在尝试 Android JSON 解析从 URL 检索并将 MySQL DB 数据设置到 TextView 中,但出现错误。我尝试了很多解决方案,但它不起作用帮助我解决这个错误
java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String org.json.JSONObject.getString(java.lang.String)' on a null object reference at
com.example.testapplication.MainActivity$GetDataFromServerIntoTextView.onPostExecute(MainActivity.java:123)at com.example.testapplication.MainActivity$GetDataFromServerIntoTextView.onPostExecute(MainActivity.java:63)
错误显示此行 textView.setText(jsonObject.getString("distance"));
我的代码
HttpResponse httpResponse;
Button button;
TextView textView;
static JSONObject jsonObject = null ;
String StringHolder = "" ;
ProgressBar progressBar;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
button = (Button)findViewById(R.id.button);
textView = (TextView)findViewById(R.id.textView);
progressBar = (ProgressBar)findViewById(R.id.progressBar);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
progressBar.setVisibility(View.VISIBLE);
new GetDataFromServerIntoTextView(MainActivity.this).execute();
}
});
}
public class GetDataFromServerIntoTextView extends AsyncTask<Void, Void, Void>
{
public Context context;
public GetDataFromServerIntoTextView(Context context)
{
this.context = context;
}
@Override
protected void onPreExecute()
{
super.onPreExecute();
}
@Override
protected Void doInBackground(Void... arg0)
{
HttpClient httpClient = new DefaultHttpClient();
String HttpURL = "https://api.myjson.com/bins/1cuzhn";
// Adding HttpURL to my HttpPost oject.
HttpPost httpPost = new HttpPost(HttpURL);
try {
httpResponse = httpClient.execute(httpPost);
StringHolder = EntityUtils.toString(httpResponse.getEntity(), "UTF-8");
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try{
JSONArray jsonArray = new JSONArray(StringHolder);
jsonObject = jsonArray.getJSONObject(0);
} catch ( JSONException e) {
e.printStackTrace();
}
catch (Exception e)
{
e.printStackTrace();
}
return null;
}
protected void onPostExecute(Void result)
{
try {
textView.setText(jsonObject.getString("distance"));
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
progressBar.setVisibility(View.GONE);
}
}
最佳答案
我修改了您的 AsyncTask 并测试了下面的代码及其工作正常。如果您发现任何问题,请告诉我。
添加以下依赖项 //OKHTTP
implementation 'com.squareup.okhttp:okhttp:2.5.0'
implementation 'com.squareup.okhttp3:logging-interceptor:3.11.0'
implementation 'org.apache.httpcomponents:httpcore:4.4.10'
和
public class GetDataFromServerIntoTextView extends AsyncTask<Void, Void,String>
{
public Context context;
public GetDataFromServerIntoTextView(Context context) {
this.context = context;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(Void... voids) {
String strUrl = "https://api.myjson.com/bins/1cuzhn";
String data = "";
InputStream iStream = null;
HttpURLConnection urlConnection = null;
try {
URL url = new URL(strUrl);
// Creating an http connection to communicate with url
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.connect();
// Reading data from url
iStream = urlConnection.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(iStream));
StringBuffer sb = new StringBuffer();
String line = "";
while ((line = br.readLine()) != null) {
sb.append(line);
}
data = sb.toString();
br.close();
} catch (Exception e) {
Log.d(TAG, "Exception while downloading url " + e.toString());
} finally {
try {
iStream.close();
} catch (IOException e) {
e.printStackTrace();
}
urlConnection.disconnect();
}
return data;
}
@Override
protected void onPostExecute(String data) {
super.onPostExecute(data);
try {
if (data != null) {
JSONArray jsonArray = new JSONArray(data);
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject jsonObject = jsonArray.getJSONObject(i);
// Here is your all data of distance and time
Log.e(TAG, "distance " + jsonObject.get("distance"));
Log.e(TAG, "time " + jsonObject.get("time"));
}
} else {
Log.e(TAG, "onPostExecute: null json object");
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}
关于java - 我在 Android JSON 解析从 URL 检索时遇到错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57567083/