我尝试将字符串电话号码重新格式化为 +1(204)867-5309
,首先将中间的点分开,然后检查输入是否有效,如果不是 抛出新的IllegalArgumentException
。但由于某种原因,即使我使用字符串生成器来更改数字的输出,它也不会改变。
提前致谢。
public class format{
public static void main (String[] args){
String phone = "204.867.5309";
System.out.println(format(phone));
}
public static String format(String phone){
char [] phoneLine = phone.toCharArray();
String [] split = phone.split("\\.");
for (char c: phoneLine){
if (phoneLine[3]=='.'
&& phoneLine[7]=='.'
&& phoneLine.length == 12
&& Character.isDigit(phoneLine[1])
&& Character.isDigit(phoneLine[0])
&& Character.isDigit(phoneLine[2])
&& Character.isDigit(phoneLine[4])
&& Character.isDigit(phoneLine[5])
&& Character.isDigit(phoneLine[6])
&& Character.isDigit(phoneLine[8])
&& Character.isDigit(phoneLine[9]))
{
StringBuilder sb = new StringBuilder(phone);
sb.append("+1");
sb.insert(2,"(");
sb.insert(6, ")");
sb.insert(10,"-");
}
else {
throw new IllegalArgumentException("not valid");
}
}
return phone;
}
}
最佳答案
你可以尝试下面的代码.output:20(48)67-5309+1
public class PhoneNumberFormat {
public static void main(String[] args) {
String phone = "204.867.5309";
System.out.println(format(phone));
}
public static String format(String phone) {
String[] split = phone.split(".");
split = phone.split("\\.");
String newPhone = "";
for (String s : split) {
newPhone = newPhone + s;
}
char[] phoneLine = newPhone.toCharArray();
StringBuilder sb = new StringBuilder();
for (char c : phoneLine) {
if (phoneLine.length == 10
&& Character.isDigit(phoneLine[1])
&& Character.isDigit(phoneLine[0])
&& Character.isDigit(phoneLine[2])
&& Character.isDigit(phoneLine[4])
&& Character.isDigit(phoneLine[5])
&& Character.isDigit(phoneLine[6])
&& Character.isDigit(phoneLine[8])
&& Character.isDigit(phoneLine[9])) {
sb = new StringBuilder(newPhone);
sb.append("+1");
sb.insert(2, "(");
sb.insert(6, ")");
sb.insert(10, "-");
} else {
throw new IllegalArgumentException("not valid");
}
}
return sb.toString();
}}
关于使用字符串生成器和拆分更改 java 电话格式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59997802/