求 2 和输入值之间所有偶数的和?
import java.util.Scanner;
public static void main(String[] args) {
//initialization and declaration of variable
int input, sum = 0;
Scanner sc = new Scanner(System.in);
//Ask user to input data
System.out.print("Enter a number you want to limit up-to : ");
input = sc.nextInt();
//Conditions
if(input < 2) {
System.out.println("Error Occurred! Please, Enter a number greater or equal to 2. ");
}
for (int i = 2; i <= input; i++ ) {
if( i % 2 == 0) {
sum += i;
}
}
}
最佳答案
您应该打印结果sum
。在 main 方法关闭之前添加 System.out.println("the sum is:"+ sum)
。完整代码如下:
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
//initialization and declaration of variable
int input, sum = 0;
Scanner sc = new Scanner(System.in);
//Ask user to input data
System.out.print("Enter a number you want to limit up-to : ");
input = sc.nextInt();
//Conditions
if(input < 2) {
System.out.println("Error Occurred! Please, Enter a number greater or equal to 2. ");
}
for (int i = 2; i <= input; i++) {
if( i % 2 == 0) {
sum += i;
}
}
System.out.println("the sum is:" + sum);
}
}
作为Tim-Hunter也就是说,你可以将i
的步长设置为2。因为如果i
是偶数,则i+1
一定是奇数。代码如下:
for (int i = 2; i <= input; i+=2) {
if( i % 2 == 0) {
sum += i;
}
}
关于java - 我尝试运行这段代码,它运行时不会抛出错误,问题是它不会执行 for 循环我只是一个初学者,所以请,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60509300/