java - 如何检测输入中的换行符

Question

我得到了这个练习，但我无法找到一种方法来捕捉新的线路。你能帮我吗？

编写一个程序，读取用户输入直到出现空行。对于每个非空字符串，程序将字符串按空格分割，然后打印包含 av 的片段，每个片段占一个新行。 这是我的代码:

public class AVClub {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        ArrayList<String> str = new ArrayList();
        String line;
        while (!(line = scanner.nextLine()).equals("")){
            str.add(line);     
        }
        for(int i=0; i<str.size();i++){
            if(str.get(i).contains("av")){
                System.out.println(str.get(i));
            }
        }

    }
}

Answer 1

您的代码中错误地实现了以下要求:

For each non-empty string, the program splits the string by spaces and then prints the pieces that contain av, each on a new line.

应该是:

import java.util.ArrayList;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        ArrayList<String> str = new ArrayList();
        String line;
        System.out.print("Enter sentences (blank line to terminate): ");
        while (!(line = scanner.nextLine()).equals("")) {
            str.add(line);
        }
        System.out.println("Words containig 'av' are: ");
        for (int i = 0; i < str.size(); i++) {
            line = str.get(i);
            String[] words = line.split("\\s+"); // Split the string on spaces
            for (String word : words) {
                if (word.contains("av")) {
                    System.out.println(word);
                }
            }
        }
    }
}

说明:你必须检查每个句子中的每个单词是否包含av。您的代码会检查每个句子中是否有 av。

示例运行:

Enter sentences (blank line to terminate): harry is a good boy
my name is avinash
Is there any seats available in the aviation training
hello world

Words containig 'av' are: 
avinash
available
aviation

注意:如果您需要以不区分大小写的方式检查 av，请按 if (word.toUpperCase().contains("AV"))。