我有一个 HttpTrigger 函数,其请求正文为
{
"id":"222",
"name":"some name"
}
我想将请求正文中的 Id 获取到 @BlobOuput 路径,如下所示
@BlobOutput(name="blob", path="input-blob/{body.id}")
有什么办法可以实现这个功能吗?
最佳答案
如何从httptrigger请求体中读取@BlobOuput路径,请引用以下步骤。
我使用以下请求正文进行测试
{
"BlobName":"test.txt",
"Content":"test"
}
- 创建自定义类作为请求正文。
public class BlobInfo {
public String Content;
public String BlobName;
public String getContent() {
return Content;
}
public void setContent(String content) {
Content = content;
}
public String getBlobName() {
return BlobName;
}
public void setBlobName(String blobName) {
BlobName = blobName;
}
}
- 函数代码
@FunctionName("HttpExample")
public HttpResponseMessage run(
@HttpTrigger(name = "req", methods = {HttpMethod.GET, HttpMethod.POST}, authLevel = AuthorizationLevel.ANONYMOUS) HttpRequestMessage<Optional<BlobInfo>> request, // request body gets automatically de-serialized into the custom object you create
@BlobOutput(name="output", path = "test/{BlobName}" // use the custom object's property you need as file name
,connection = "AzureWebJobsStorage") OutputBinding<String> outputItem,
final ExecutionContext context) throws IOException {
context.getLogger().info("Java HTTP trigger processed a request.");
BlobInfo body = request.getBody().get();
context.getLogger().info(body.Content);
context.getLogger().info(body.BlobName);
outputItem.setValue("Hello World!");
return request.createResponseBuilder(HttpStatus.OK).body("success").build();
}
- 测试
POST <function url>
Content-Type:application/json
{
"BlobName":"test.txt",
"Content":"test"
}
关于java - Azure Java函数,获取BlobOutput路径注释中的HttpTrigger主体属性值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60970419/