java - 为什么我没有得到 jsonObject.getString ("weather"的任何输出？

Question

 protected void onPostExecute(String s)
        {
            super.onPostExecute(s);
            log.i("URL" , s) // I am getting output for this part
            try
                {
                    JSONObject jsonObject = new JSONObject(s); // JSONObject Created
                    String weatherInfo = jsonObject.getString("weather"); // Fetching info from weather section

                    Log.i("JSON", urlResult); // But not for this part

                    JSONArray jsonArray = new JSONArray(weatherInfo);
                    for(int i = 0; i < jsonArray.length(); i++)
                    {
                        JSONObject jsonPart = jsonArray.getJSONObject(i);

                        // Not getting output for this two lines also
                        Log.i("main", jsonPart.getString("main")); // fetching info from 'main' section
                        Log.i("description", jsonPart.getString("description"));  // fetching info from 'description' section
                    }
                }
            catch (Exception e)
                {
                    e.printStackTrace(); // Handling Error
                }
        }

我正在尝试从 openworldmap.org 获取天气信息。我使用的是Android Studio 3.0。我传递到代码中的 URL 是 https://samples.openweathermap.org/data/2.5/weather?q=London,uk&appid=b6907d289e10d714a6e88b30761fae22

Answer 1

你可以调用getJSONArray，

//String weatherInfo = jsonObject.getString("weather"); // Fetching info from weather section

//Log.i("JSON", urlResult); // But not for this part
//JSONArray jsonArray = new JSONArray(weatherInfo);
JSONArray jsonArray = jsonObject.getJSONArray("weather");

在 for 循环中你应该使用 get(i);

JSONObject jsonPart = jsonArray.get(i); //jsonArray.getJSONObject(i);