java - 如何使用 JUNG 的 Edmonds Karp 获得每个可能的源/汇节点对的最大流量?

标签 java algorithm graph jung max-flow

我有一些简单的 Java/JUNG 代码,可以创建有向图,添加一些带有权重和容量值的边,并运行从源节点到汇节点的最大流量分析。

如果你有:A --- (capacity 2) -----> B ---- (capacity 5)----> C 并且想要找到从A->C的最大流量,它将为 2。

import edu.uci.ics.jung.algorithms.flows.EdmondsKarpMaxFlow;
import edu.uci.ics.jung.graph.DirectedSparseMultigraph;
import edu.uci.ics.jung.graph.util.EdgeType;
import org.apache.commons.collections15.Factory;
import org.apache.commons.collections15.Transformer;

import java.util.HashMap;
import java.util.Map;

public class stack {
    static int edgeCount = 0;

    static class MyNode {
        int id;
        public MyNode(int id) {
            this.id = id;
        }
        public String toString() {
            return "V"+id;
        }
    }

    static class MyLink {

        double capacity;
        double weight;
        int id;

        public MyLink(double weight, double capacity) {
            this.id = edgeCount++;
            this.weight = weight;
            this.capacity = capacity;
        }
        public String toString() {
            return "E"+id;
        }

    }
    public static void main(String[] args){
        DirectedSparseMultigraph<MyNode, MyLink> g = new DirectedSparseMultigraph<MyNode, MyLink>();

        Transformer<MyLink, Double> capTransformer = new Transformer<MyLink, Double>(){
            public Double transform(MyLink link) {
                return link.capacity;
            }
        };

        Map<MyLink, Double> edgeFlowMap = new HashMap<MyLink, Double>();
        // This Factory produces new edges for use by the algorithm
        Factory<MyLink> edgeFactory = new Factory<MyLink>() {
            public MyLink create() {
                return new MyLink(1.0, 1.0);
            }
        };

        // Create some MyNode objects to use as vertices
        MyNode n1 = new MyNode(1);
        MyNode n2 = new MyNode(2);
        MyNode n3 = new MyNode(3);
        MyNode n4 = new MyNode(4);
        MyNode n5 = new MyNode(5);
        MyNode n6 = new MyNode(6);
        MyNode n7 = new MyNode(7);
        // Add some directed edges along with the vertices to the graph
        g.addEdge(new MyLink(2.0, 48),n1, n2, EdgeType.DIRECTED);
        g.addEdge(new MyLink(2.0, 58),n2, n3, EdgeType.DIRECTED);
        g.addEdge(new MyLink(3.0, 192), n3, n5, EdgeType.DIRECTED);
        g.addEdge(new MyLink(2.0, 48), n5, n4, EdgeType.DIRECTED);
        g.addEdge(new MyLink(2.0, 20), n6, n1, EdgeType.DIRECTED);
        g.addEdge(new MyLink(8, 24), n7, n4, EdgeType.DIRECTED);

        System.out.println("RUNNING EDMONDS KARP MAX FLOW FOR SOURCE " + n1.toString() + " TO SINK " + n2.toString());
        EdmondsKarpMaxFlow<MyNode, MyLink> edk = new EdmondsKarpMaxFlow(g, n1, n2, capTransformer, edgeFlowMap, edgeFactory);
        edk.evaluate();
        System.out.println("The max flow is: " + edk.getMaxFlow());
    }
}

运行此命令将输出:

RUNNING EDMONDS KARP MAX FLOW FOR SOURCE V1 TO SINK V2 The max flow is: 48

如何编写一个算法,使其在每对可能的源和接收器上运行,以便我可以看到图中所有路径的最大流量?对这个东西完全陌生,所以任何东西都有帮助!

最佳答案

只需为每对节点运行算法即可。没有已知的算法对于有向图更有效:All pair Maximum Flow

关于java - 如何使用 JUNG 的 Edmonds Karp 获得每个可能的源/汇节点对的最大流量?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61330222/

相关文章:

algorithm - 递归删除数组中的元素

ruby - 给定元素(或索引)周围的子数组

java - 我可以根据比例缩放ValueAxis吗?

matlab - 如何找到多元非线性方程的数值近似?

javascript - Highcharts:不同屏幕尺寸断点上的渲染器定位问题

java - ThreadLocal 线程安全吗?

java - 获取特定日期范围

java - 生成具有特定 6 位小数的随机 double

java - 初始化 servlet 时如何传递引用

c++ - 限制浮点精度?