我有一个 SQL 查询
SELECT * FROM Thing AS a JOIN Thing_Property AS b ON a.id=b.Thing_ID
JOIN Property AS c ON b.properties_ID = c.id
JOIN Item AS d ON c.item_ID = d.id
ORDER BY a.name, d.name
我用 Eclipselink 创建我的对象模型。 这是模型:
@SuppressWarnings("serial")
@Entity
public class Thing implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
private int id;
private String name;
@OneToMany(cascade=CascadeType.ALL)
@PrivateOwned
private List<Property> properties = new ArrayList<Property>();
...
// getter and setter following here
}
public class Property implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
private int id;
@OneToOne
private Item item;
private String value;
...
// getter and setter following here
}
public class Item implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
private int id;
private String name;
....
// getter and setter following here
}
// Code end
但我不知道如何让 Eclipselink 从该查询创建模型。你能帮忙吗?
最佳答案
您将需要使用 API EntityManager.createNativeQuery(String sqlString, Class resultClass);
entityManager.createNativeQuery("SELECT * FROM Thing AS a JOIN Thing_Property AS b ON a.id=b.Thing_ID JOIN Property AS c ON b.properties_ID = c.id JOIN Item AS d ON c.item_ID = d.id ORDER BY a.name, d.name ", Thing.class);
关于java - Eclipselink:从 JOIN 查询创建对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2578127/