java - OnClick 方法杀死 Android 应用程序

Question

我有一个简单的消息应用程序，它获取 editText 框的文本并将其发送到服务器。我想做的就是当文本发送到服务器时，我希望重置 editText 框。

这是我的代码，可以运行，但是它不会重置 editText 框:

public void sendMessage(View v) {
        Editable messagetext;

        messagetext = message.getText();

        final SharedPreferences prefs = PreferenceManager
                .getDefaultSharedPreferences(getBaseContext());

        username = prefs.getString("username", "null");

        where = prefs.getString("chat", "null");
        message = (EditText) findViewById(R.id.inptbox);

        function = new Functions();

        response = function
                .sendMessage(username, where, messagetext.toString());

    }

如果我再添加一行代码，为了重置该框，我的应用程序就会终止:

public void sendMessage(View v) {
    Editable messagetext;

    messagetext = message.getText();
        message.setText("");
    final SharedPreferences prefs = PreferenceManager
            .getDefaultSharedPreferences(getBaseContext());

    username = prefs.getString("username", "null");

    where = prefs.getString("chat", "null");
    message = (EditText) findViewById(R.id.inptbox);

    function = new Functions();

    response = function
            .sendMessage(username, where, messagetext.toString());

}

我得到的错误(请耐心等待，我不是那么好的 logcat)是:

E/AndroidRuntime(7207): java.lang.IllegalStateException: Could not execute method of the activity

全局变量列表:

String username = "";
    Functions function;
    EditText message;
    String response = "";
    String where = "";
    String inboxx;

Answer 1

...
messagetext = message.getText();                 
...
message = (EditText) findViewById(R.id.inptbox);  
...

这些的顺序不应该颠倒吗？在调用 getText 之前，您应该需要说明“消息”是什么。