java - 如何在 Spring XML 配置中将 long 设置为十六进制

Question

我正在尝试做这样的事情:

<bean id="myBean" class="com.example.SomeThing">
    <property name="longValue">
        <bean class="java.lang.Long">
            <constructor-arg value="0x0418a14372d4186eL" type="long"/>
        </bean>
    </property>
</bean>

但这会导致以下异常:

Caused by: org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'java.lang.Long#19190b75' defined in file [/apollo/env/path/to/config.xml]: Unsatisfied dependency expressed through constructor argument with index 0 of type [java.lang.String]: Ambiguous constructor argument types - did you specify the correct bean references as constructor arguments?

Answer 1

我想你想要factory-method <bean>的参数:

<bean id="myBean" class="com.example.SomeThing">
    <property name="longValue">
        <bean class="java.lang.Long" factory-method="decode">
            <constructor-arg value="0x0418a14372d4186" />
        </bean>
    </property>
</bean>

(请注意缺少“L”后缀。)