这是我的编码: 出于某种原因，最后，当我尝试返回winscounter和losscounter时，它显示无法访问的语句，但不适用于tiescounter。我不明白为什么!如果有人能回答这个问题，将不胜感激!
public class RockPaperScissors {
/**
* @param args the command line arguments
*/
static int value; //computer's choice
static int choice; //user choice
static int tiescounter = 0;
static int winscounter = 0;
static int losscounter = 0;
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader (new InputStreamReader (System.in));// user input
int repeat;
do {
System.out.println("ROCK PAPER SCISSORS"+
"\n===================");
System.out.println("\n1=Rock" +
"\n2=Paper" +
"\n3=Scissors" +
"\n===========" +
"\nChoose:");
choice = Integer.parseInt(br.readLine());
if (choice !=1 && choice !=2 && choice !=3) {
do{
System.out.println("\nError. Please choose Rock, Paper or Scissors.");
choice = Integer.parseInt(br.readLine());
}
while (choice !=1 && choice !=2 && choice !=3);
}
System.out.println();
if (choice == 1){
System.out.println("You have chosen Rock.");
}
else if (choice ==2){
System.out.println("You have chosen Paper.");
}
else if(choice == 3){
System.out.println("You have chosen Scissors.");
}
randomWholeNumber();
if (value == 1){
System.out.println("The computer has chosen Rock." );
}
else if (value == 2){
System.out.println("The computer has chosen Paper." );
}
else if (value == 3){
System.out.println("The computer has chosen Scissors." );
}
determineOutcome();
System.out.println("Ties:"+ tiescounter);
System.out.println("Wins: " + winscounter);
System.out.println("Losses: " + losscounter);
repeat = Integer.parseInt(br.readLine());
}
while (repeat==1);
}
public static int randomWholeNumber(){
do{
value=0;//resets random number
//generates and returns a random number within user's range
value = (int) ((Math.random()*3)+1);
}
while((value>3)||(value<1));
return (value);
}
public static int determineOutcome(){
if (value == choice){
System.out.println("\nYOU'VE TIED");
do{
tiescounter+=1;
}
while (tiescounter != tiescounter);
}
else if (value == 1){ //Rock
if (choice == 2){ //Paper
System.out.println("\nYOU'VE WON");
do{
winscounter +=1;
}
while (winscounter != winscounter);
}
else if (choice == 3){ //Scissors
System.out.println("\nYOU'VE LOST");
do{
losscounter+=1;
}
while(losscounter!=losscounter);
}
}
else if (value == 2){ //Paper
if (choice == 1){ //Rock
System.out.println("\nYOU'VE LOST");
do{
losscounter+=1;
}
while(losscounter!=losscounter);
}
else if (choice == 3){ //Scissors
System.out.println("\nYOU'VE WON");
do{
winscounter +=1;
}
while (winscounter != winscounter);
}
}
else if (value == 3){ //Scissors
if (choice == 1){ //Rock
System.out.println("\nYOU'VE WON");
do{
winscounter +=1;
}
while (winscounter != winscounter);
}
else if (choice == 2){ //Paper
System.out.println("\nYOU'VE LOST");
do{
losscounter+=1;
}
while(losscounter!=losscounter);
}
}
return(tiescounter);
return(winscounter);
return(losscounter);
}
}
最佳答案
您不能同时从一个方法返回 3 个不同的变量。在这种情况下，return(tiescounter); 始终执行，并立即终止该方法。因此接下来的两行变得无法访问。
将 defineOutcome() 方法声明为 void，即 public static void recognizeOutcome()，并删除其中的所有 return 语句。您的程序将会运行。
关于java - 无法访问的声明？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16139376/