我在使用 java 泛型时遇到问题。 当我从迭代器使用 next() 时,它不会返回与我实例化它相同类型的对象。所以我收到一个不兼容的类型错误。 有人可以帮忙吗?
当我编译链接列表类时,我还收到了 Xlint 警告。
public class LinkedList<Type>
{
private Node<Type> sentinel = new Node<Type>();
private Node<Type> current;
private int modCount;
public LinkedList()
{
// initialise instance variables
sentinel.setNext(sentinel);
sentinel.setPrev(sentinel);
modCount = 0;
}
public void prepend(Type newData)
{
Node<Type> newN = new Node<Type>(newData);
Node<Type> temp;
temp = sentinel.getPrev();
sentinel.setPrev(newN);
temp.setNext(newN);
newN.setPrev(temp);
newN.setNext(sentinel);
modCount++;
}
private class ListIterator implements Iterator
{
private int curPos, expectedCount;
private Node<Type> itNode;
private ListIterator()
{
curPos =0;
expectedCount = modCount;
itNode = sentinel;
}
public boolean hasNext()
{
return (curPos < expectedCount);
}
public Type next()
{
if (modCount != expectedCount)
throw new ConcurrentModificationException("Cannot mutate in context of iterator");
if (!hasNext())
throw new NoSuchElementException("There are no more elements");
itNode = itNode.getNext();
curPos++;
current = itNode;
return (itNode.getData());
}
}
}
这是创建列表并填充不同类型的形状后主类中发生错误的地方。
shape test;
Iterator iter = unsorted.iterator();
test = iter.next();
最佳答案
Iterator
is a generic interface ,但是你的ListIterator
既不是泛型也不是参数化Iterator
。首先制作 ListIterator
实现Iterator<Type>
:
private class ListIterator implements Iterator<Type> {
// the rest should be fine
}
或制作ListIterator
也是通用的(更复杂):
private class ListIterator<T> implements Iterator<T>
{
private int curPos, expectedCount;
private Node<T> itNode;
private ListIterator()
{
curPos = 0;
expectedCount = modCount;
itNode = sentinel;
}
public boolean hasNext()
{
return (curPos < expectedCount);
}
public T next()
{
// snip
}
}
关于java - 正确使用java泛型?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16391480/