我是 Web 服务和 Spring 的新手。我有一个像这样的网络服务方法:
@WebMethod(operationName = "docSearch")
public ServiceResponse docSearch(@WebParam(name = "docNum") String docNum) {
//TODO lots of TODOs here:
docService = getDocService();
ServiceResponse serviceResponse = docService.docSearchService(docNum);
return serviceResponse;
}
使用此服务:
@Transactional
public ServiceResponse docSearchService(ServiceRequest serviceRequest, String docNum) {
//TODO lots of TODOs here:
ServiceResponse serviceResponse = new ServiceResponse();
serviceResponse = docDao.docSearchDAO(serviceRequest, docNum);
return serviceResponse;
}
对应的DAO是:
public ServiceResponse docSearchDAO(ServiceRequest serviceRequest, String docNum) {
Session session = sessionFactory.getCurrentSession();
List<doc> temp = session.createCriteria(Doc.class)
.add(Restrictions.eq("id", docNum))
.list();
if (temp != null && temp.size() > 0) {
serviceResponse.setDescription("Service response successfully implemented);
return serviceResponse;
} else {
serviceResponse.setDescription("Service response was not successfully implemented);
return serviceResponse;
}
}
我想知道在 Web 方法、服务层或 DAO 层中填充此 ServiceResponse 对象的最佳方式是什么?
最佳答案
我会在你的网络方法中说。 Web服务应该是调用服务层的接口(interface)。它应该将传入请求转换为服务层可以理解的内容,并将结果转换为 Web 服务可以发送的内容。
该服务通常是应用程序的可重用部分,可以在 Web 服务和 Web 应用程序(带有 Controller )之间重用,或者可以通过批量插入来重用。基本上,调用服务(包含业务逻辑)的所有内容都是服务的接口(interface)层。
Controllers provide access to the application behavior that you typically define through a service interface. Controllers interpret user input and transform it into a model that is represented to the user by the view. Spring implements a controller in a very abstract way, which enables you to create a wide variety of controllers. Reference Guide
对我来说,这适用于与服务层交互的应用程序的每个部分。它基本上从/到服务层理解的东西转换。这是a blog链接到一些有趣的信息(在更广泛的架构层面上)。
链接:
关于java - 在 Web 方法、服务层或 DAO 层中创建服务响应?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18638783/