Java 射弹角度

Question

所以，我正在制作一个平台游戏，您应该能够拖动鼠标以从角色沿鼠标释放的方向发射射弹，速度为两点之间的距离。

    public void mouseDragged(MouseEvent e) {
    player.setAiming(true);
    Point2D.Float aimpoint = new Point2D.Float(e.getXOnScreen(), e.getYOnScreen());
    player.setAimpoint(aimpoint);
    player.setAimDistance(GetDistanceToPoint(player.getPos(), aimpoint));
}
public static float GetAngleOfLine(Point2D.Float p1, Point2D.Float p2) { 
    double xDiff = p2.x - p1.x; 
    double yDiff = p2.y - p1.y; 
    System.out.println("P1X: " + p1.x + " P1Y: " + p1.y + " P2X: " + p2.x + " P2Y: " + p2.y + " Angle: " + Math.toDegrees(Math.atan2(yDiff, xDiff)));
    return (float) Math.toDegrees(Math.atan2(yDiff, xDiff));
}
public static float GetDistanceToPoint(Point2D.Float p1, Point2D.Float p2){
    float distance = (float) Math.sqrt(Math.pow(p2.y - p1.y, 2) + Math.pow((p2.x - p1.x), 2));
    return distance;
}

然后，当鼠标松开时，

player.setAimingangle(GetAngleOfLine(player.getPos(), player.getAimpoint()));

然后创建一个弹丸，其中角度为player.aimingangle，强度为player.aimingdistance:

        float yvel = (float) (strength * Math.sin(angle));
    float xvel = (float) (strength * Math.cos(angle));

我收到了非常奇怪的射弹，它们飞得到处都是。

Answer 1

Math.sin 和 Math.cos 采用弧度参数，但您向它们提供度数。