java - 返回数组中包含等于槽索引的值的槽数量的计数

Question

我正在尝试编写一个程序，在生成随机数后，返回数组中包含等于槽索引的值的槽数，然后将数组的每个元素打印在单独的与星号对齐。 (假设看起来像这样:)

Enter the array size: 4
a[0] = 2
a[1] = 1 *
a[2] = 0
a[3] = 2
There are 1 slots where the index is the same as the value.

但我失败得很惨，任何朝着正确方向的插入将不胜感激。这是我到目前为止所拥有的:

import java.util.Scanner;

public class RandomArray {

public static void main(String[] args) {
    Scanner in = new Scanner(System.in);

            int i;
    System.out.println("Enter the array size: ");
            i = in.nextInt();

}

/**
 * Fills an array with random integers in the range from zero to one less
 * than the array size.
 * 
 * @param array
 *            the array to fill with random integers
 */
public static void fillArrayWithRandomInts(int array[]) {
    java.util.Random random = new java.util.Random(13);
    for (int i = 0; i < array.length; ++i)
        array[i] = (int) (random.nextDouble() * array.length);
}

public static int countSlotsWithIndexEqualToValue(int array[]) {

    int[] value = new int[13];

    for (int i = 0; i < array.length; i++) {

        if (value[13] == array[13])
            ;

    }
    return value[13];

}

public static void printArray(int array[]) {

}

}

Answer 1

您需要以相同的方法将支票和打印结合起来。如果您需要统计有多少个这样的组合，则需要添加一个计数器。

public static void countSlotsAndPrint(int[] a) {
    int counter = 0;
    for (int i = 0; i < a.length; i++) {
        System.out.print("a[" + i + "] = " + a[i]); // print the array as per required
        if (i == array[i]){
            System.out.println(" *"); // if index is equal to the value, then print the *            
            counter++;
        } else {
            System.out.println(); // blank line to go to the next line
        }
    }
    System.out.println("There are " + counter + " slots where the index is the same as the value.");
}