我的 Android 应用程序正在发送短信并且工作正常。但是,当用户输入错误号码时,发送的短信不会显示错误消息。因此,用户不知道他输入了错误的号码。我该如何解决这个问题?
Activity.java
StringTokenizer st=new StringTokenizer(phoneNo,",");
while (st.hasMoreElements())
{
String tempMobileNumber = (String)st.nextElement();
if(tempMobileNumber.length()>0 && sms.trim().length()>0)
{
sendSMS(tempMobileNumber, sms);
}
else
{
Toast.makeText(getBaseContext(),
"Please enter both phone number and message.",
Toast.LENGTH_SHORT).show();
}
}
private void sendSMS(String phoneNumber, String message)
{
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0,
new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
new Intent(DELIVERED), 0);
//---when the SMS has been sent---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS sent",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(getBaseContext(), "Generic failure",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(getBaseContext(), "No service",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(getBaseContext(), "Null PDU",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(getBaseContext(), "Radio off",
Toast.LENGTH_SHORT).show();
break;
}
}
},new IntentFilter(SENT));
//---when the SMS has been delivered---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS delivered",
Toast.LENGTH_SHORT).show();
break;
case Activity.RESULT_CANCELED:
Toast.makeText(getBaseContext(), "SMS not delivered",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(DELIVERED));
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);
}
最佳答案
您需要验证用户输入是否是电话号码
例如:手机号码必须为 10 位
String number="2525252212"
Pattern mobileNo= Pattern.compile("\\d{10}");
Matcher matcher = mobileNo.matcher(number);
if (matcher.matches()) {
//go on
} else {
//Show Dialog
}
关于java - 发送短信时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22655601/