当我运行此代码时,我收到 IllegalStateException: Cannotforward after respons has been commited。抱歉,我是 servlet 新手。我应该怎么做才能解决这个问题?这发生在这一行:
RequestDispatcher rd = request.getRequestDispatcher("/displayjobs.jsp");
rd.forward(request, response);
这是异常的堆栈跟踪:
java.lang.IllegalStateException: Cannot forward after response has been committed
schedule.doGet(schedule.java:71)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)
这是我的 servlet 代码的其余部分。 编辑:我还包含了我的 jsp 代码,因为我现在在第 2 行遇到了 NPE:
1 List data = (List)request.getAttribute("jobsData);
2 for(itr = data.iterator(); itr.hasNext();)
这意味着由于某种原因数据为空,而不是具有 JobsData 的信息。
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
PrintWriter out = response.getWriter();
try{
Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
String connectionUrl = "jdbc:sqlserver://10.11.1.246;databaseName=Test;integratedSecurity=false;user=sa;password=S0l1dConcepts";
Connection con = DriverManager.getConnection(connectionUrl);
String query = "select * from jobs";
stmt = con.createStatement();
res = stmt.executeQuery(query);
while(res.next()){
list.add(res.getString(1));
list.add(res.getString(2));
list.add(res.getString(3));
list.add(res.getString(4));
list.add(res.getString(5));
list.add(res.getString(6));
list.add(res.getString(7));
list.add(res.getString(8));
list.add(res.getString(9));
list.add(res.getString(10));
}
res.close();
}
catch(Exception e){
RequestDispatcher rd = request.getRequestDispatcher("/error.jsp");
rd.forward(request, response);
}
finally{
request.setAttribute("jData", list);
RequestDispatcher rd = request.getRequestDispatcher("/displayjobs.jsp");
rd.forward(request, response);
list.clear();
out.close();
}
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
PrintWriter out = response.getWriter();
try{
Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
String connectionUrl = "jdbc:sqlserver://10.11.1.246;databaseName=Test;integratedSecurity=false;user=sa;password=S0l1dConcepts";
Connection con = DriverManager.getConnection(connectionUrl);
String query = "select * from jobs";
stmt = con.createStatement();
res = stmt.executeQuery(query);
while(res.next()){
list.add(res.getString(1));
list.add(res.getString(2));
list.add(res.getString(3));
list.add(res.getString(4));
list.add(res.getString(5));
list.add(res.getString(6));
list.add(res.getString(7));
list.add(res.getString(8));
list.add(res.getString(9));
list.add(res.getString(10));
}
res.close();
}
catch(Exception e){
RequestDispatcher rd = request.getRequestDispatcher("/error.jsp");
rd.forward(request, response);
}
finally{
request.setAttribute("jData", list);
RequestDispatcher rd = request.getRequestDispatcher("/displayjobs.jsp");
rd.forward(request, response);
list.clear();
out.close();
}
}
}
这是 JSP 代码:
<%@page import="java.util.List" %>
<%@page import="java.util.Iterator" %>
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Scheduling</title>
</head>
<body>
<table>
<%Iterator itr;%>
<%List data = (List)request.getAttribute("jobsData");
for(itr = data.iterator(); itr.hasNext();){
%>
<tr>
<% String s = (String) itr.next();%>
<td><%=s%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><%=itr.next()%></td>
<td><input type="submit" value="Edit" name="edit" onclick ="editRecord(<%=s%> %>);"></td>
<td><input type="submit" value="Delete" name="delete" onclick ="deleteRecord(<%=s%> %>);"></td>
<%} %>
</tr>
</table>
最佳答案
问题很简单。异常被捕获,响应从 catch block 委托(delegate),并再次从 finally block 委托(delegate)。
您应该做的是有一个地方来委托(delegate)您的响应
请注意:- 响应只能提交一次
boolean exceptionOcured =false;
try{
// your code
}
catch(Exception e){
exceptionOcured =true;
}
finally{
// your code to release resources
}
if(exceptionOcured){
RequestDispatcher rd = request.getRequestDispatcher("/error.jsp");
rd.forward(request, response);
}else{
RequestDispatcher rd = request.getRequestDispatcher("/displayjobs.jsp");
rd.forward(request, response);
}
关于java - 提交响应后无法转发 Servlet 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25047015/