java - 将 XML 转换为 Java Map<String, Integer>

Question

我正在尝试将 XML 转换为 Java 代码。该 XML 位于不同的文件中；它将单词与数字(概率分布)进行匹配，如下所示:

<?xml version="1.0" encoding="UTF-8" ?>
<root>
   <Durapipe type="int">1</Durapipe>
   <EXPLAIN type="int">2</EXPLAIN>
   <woods type="int">2</woods>
   <hanging type="int">3</hanging>
   <hastily type="int">2</hastily>
   <localized type="int">1</localized>
   <Schuster type="int">5</Schuster>
   <regularize type="int">1</regularize>
   <LASR type="int">1</LASR>
   <LAST type="int">22</LAST>
   <Gelch type="int">2</Gelch>
   <Gelco type="int">26</Gelco>
   .......
</root>

我正在尝试将其转换为 Java map ，这是我为此使用的代码:

XStream xstream = new XStream();
    @SuppressWarnings("unchecked")
    Map<String, Integer> englishCorpusProbDist = (Map<String, Integer>)xstream.fromXML(new File("LocationOfFileOnMyComputer/frequencies.xml"));

目前，每当我尝试运行上述 Java 代码时，我的控制台都会出现以下异常:

Exception in thread "main" com.thoughtworks.xstream.mapper.CannotResolveClassException: root
at com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:79)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.DynamicProxyMapper.realClass(DynamicProxyMapper.java:55)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.PackageAliasingMapper.realClass(PackageAliasingMapper.java:88)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.ClassAliasingMapper.realClass(ClassAliasingMapper.java:79)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.ArrayMapper.realClass(ArrayMapper.java:74)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.SecurityMapper.realClass(SecurityMapper.java:71)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30)
at com.thoughtworks.xstream.mapper.CachingMapper.realClass(CachingMapper.java:47)
at com.thoughtworks.xstream.core.util.HierarchicalStreams.readClassType(HierarchicalStreams.java:29)
at com.thoughtworks.xstream.core.TreeUnmarshaller.start(TreeUnmarshaller.java:133)
at com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.unmarshal(AbstractTreeMarshallingStrategy.java:32)
at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1185)
at com.thoughtworks.xstream.XStream.unmarshal(XStream.java:1169)
at com.thoughtworks.xstream.XStream.fromXML(XStream.java:1133)
at com.thoughtworks.xstream.XStream.fromXML(XStream.java:1075)
at ProductAttributeExtractor.main(ProductAttributeExtractor.java:23)

这是一篇相关的文章，但我的问题是增加了一层复杂性，因为我的 XML 将字符串与整数相匹配，不幸的是 Java Map 不能使用整数，它必须使用整数(这非常令人沮丧):How to convert XML to java.util.Map and vice versa

如果您能提供任何帮助，我们将不胜感激。提前致谢!

Answer 1

您需要注册您的MapConverter，即实现Converter的类

xstream.registerConverter(new MapEntryConverter());

希望有帮助